如何刪除列表中兩個值的所有出現？

Question

我想使用一行刪除列表中兩個值的所有出現。我嘗試了filter + lambda方法和列表理解，但它不按我期望的方式工作。

喜歡的東西：

s2 = [0, 0, 3, 11, 14, 17, 18, 18] 
# I want to remove all 0 and 18 from s2 list 
# i.e. I want output: s2_filter = [3, 11, 14, 17] 

s2_filter = filter (lambda a: a != 0 or 18, s2) 
>>> s2 = [0, 0, 3, 11, 14, 17, 18, 18] # not what I'm expecting 

s2_filter = [i for i in s2 if i != 0 or 18] 
>>> s2 = [0, 0, 3, 11, 14, 17, 18, 18] # not what I'm expecting 

我想有一些錯誤的or，但我想不出我應該怎麼正確地寫這個。

你能幫忙嗎？

Answer 1

你可以只篩選了，如果我在非理想的名單是不是：

s2 = [0, 0, 3, 11, 14, 17, 18, 18] 
s2_filter = [i for i in s2 if i not in [0, 18]] 
s2_filter 
[3, 11, 14, 17]