php中使用類的多個數據庫連接

Question

我正在創建一個類conn.php，其中我使用相同的用戶和密碼連接到三個數據庫。 conn.php的代碼在下面給出：

<?php 

    /** 
    * @author Hira Tiwari 
    * @copyright 2013 
    */ 

    class createConnection //create a class for make connection 
    { 
     var $host="localhost"; 
     var $username=""; // specify the sever details for mysql 
     var $password=""; 
     var $database1=""; 
     var $database2=""; 
     var $database3=""; 
     var $myconn; 

     function connectToDatabase() // create a function for connect database 
     { 

      $conn= mysql_connect($this->host,$this->username,$this->password); 

      if(!$conn)// testing the connection 
      { 
       die ("Cannot connect to the database"); 
      } 

      else 
      { 
       $this->myconn = $conn; 
      } 

      return $this->myconn; 
     } 

     function selectDatabase1() // selecting the database. 
     { 

      mysql_select_db($this->database1); //use php inbuild functions for select database 

      if(mysql_error()) // if error occured display the error message 
      { 
       echo "Cannot find the database ".$this->database1; 
      }  
     } 

     function selectDatabase2() // selecting the database. 
     { 

      mysql_select_db($this->database2); //use php inbuild functions for select database 

      if(mysql_error()) // if error occured display the error message 
      { 
       echo "Cannot find the database ".$this->database2; 
      } 

     } 

     function selectDatabase3() // selecting the database. 
     { 
      mysql_select_db($this->database3); //use php inbuild functions for select database 

      if(mysql_error()) // if error occured display the error message 
      { 
       echo "Cannot find the database ".$this->database3; 
      } 

     } 

     function closeConnection() // close the connection 
     { 
      mysql_close($this->myconn); 
     } 
    } 
?> 

我正在這個類在另一個PHP文件的對象從表 包括（conn.php'）訪問所述數據;

$connection = new createConnection(); //i created a new object 
$connn = $connection->connectToDatabase(); // connected to the database 
$connection->selectDatabase1();// closed connection 

它不聯機工作（顯示拒絕用戶temptes2_data'@ 'localhost' 的SELECT命令），但在本地主機上正常工作。如果我正在另一個php文件中建立連接並連接到數據庫，那麼工作正常並選擇所有數據。但是如果我在函數conn.php中建立連接，那麼它不起作用。誰能幫我 ？

如果我想它，它做工精細

<?php 

    $host="localhost"; 
    $username=""; 
    $password=""; 
    $database1=""; 

    $conn= mysql_connect($host,$username,$password) or die(mysql_error()); 

    if(!$conn)// testing the connection 
    { 
     die ("Cannot connect to the database"); 
    } 
    mysql_select_db($database1,$conn) or die(mysql_error()); 
    $query = mysql_query("select * from mptblevent") or die(mysql_error()); 
    while($row = mysql_fetch_array($query)) 
    { 
     echo $row['even_sid']."<br>"; 
    } 

?> 

Answer 1

STOP！

不要嘗試在mysql_中執行此操作，請使用mysqli。它的面向對象特性使你正在嘗試做的小事：

$DB_NAME = "db1"; 
$DB_HOST = "host"; 
$DB_USER = "user"; 
$DB_PASS = "pass"; 
$mysqli1 = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME); 

$DB_NAME = "db2"; 
$mysqli2 = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME); 


$query = "SELECT .... "; 

$result1 = $mysqli1->query($query) or die($mysqli1->error); 
$result2 = $mysqli2->query($query) or die($mysqli2->error); 

等很多更容易和遷移真的不採取了很多的努力。我最近自己做了。一個小時左右〜15個PHP腳本