從字符串從一個數組

Question

下面替換特殊字符是我的代碼：

NSString *str = [EpiC objectAtIndex:indexPath.row]; 
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\/"]; 
str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\"]; 
NSLog(@"%@", str); 

它顯示錯誤如下：在該行 未知的轉義序列：

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\/"]; 

和意外「@ '在程序中，在這一行：

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\"]; 

Answer 1

未知的轉義序列表示您必須使用第二個反斜槓來反轉反斜槓。

NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"]; 

的反斜線解決意外「@」在程序錯誤了。

Answer 2

不喜歡

NSString *str = @"FSJ\/6356232"; 
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"]; 
str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\\"]; 
     NSLog(@"%@", str); 

你的

Answer 3

輸出做如下我爲你肯定的工作。

NSString *str = @"FSJ\/6356232"; 
NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@"\\/"]; 
str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @"\\"]; 
     NSLog(@"%@", str);