PHP：我如何從JSON數組中獲取屬性？

Question

我有以下的JSON數組：

<?php  
$json = { 
    "status": "OK", 
    "results": [ { 
    "types": [ "street_address" ], 
    "formatted_address": "5721 N Northcott Ave, Chicago, IL 60631, USA", 
    "address_components": [ { 
     "long_name": "5721", 
     "short_name": "5721", 
     "types": [ "street_number" ] 
    }, { 
     "long_name": "Illinois", 
     "short_name": "IL", 
     "types": [ "administrative_area_level_1", "political" ] 
    }, { 
     "long_name": "60631", 
     "short_name": "60631", 
     "types": [ "postal_code" ] 
    } ], 
    "geometry": { 
     "location": { 
     "lat": 41.9858860, 
     "lng": -87.7907460 
     }, 
     "location_type": "ROOFTOP", 
     "viewport": { 
     "southwest": { 
      "lat": 41.9827384, 
      "lng": -87.7938936 
     }, 
     "northeast": { 
      "lat": 41.9890336, 
      "lng": -87.7875984 
     } 
     } 
    } 
    } ] 
}; 
?> 

使用PHP，我如何才能從上面我的JSON數組的geometery->location->lat & lng值？

例如（僞代碼）：

<?php 
$lat = $json['geometry']['location']['lat']; // 41.9858860 
$lng = $json['geometry']['location']['lng']; // -87.7907460 
?> 

Answer 1

您使用json_decode，然後使用$var->results[0]->geometry->location->lat;。

json_decode產生的結構如下：

 
object(stdClass)[1] 
    public 'status' => string 'OK' (length=2) 
    public 'results' => 
    array 
     0 => 
     object(stdClass)[2] 
      public 'types' => 
      array 
       0 => string 'street_address' (length=14) 
      public 'formatted_address' => string '5721 N Northcott Ave, Chicago, IL 60631, USA' (length=44) 
      public 'address_components' => 
      array 
       0 => 
       object(stdClass)[3] 
        public 'long_name' => string '5721' (length=4) 
        public 'short_name' => string '5721' (length=4) 
        public 'types' => 
        array 
         0 => string 'street_number' (length=13) 
       1 => 
       object(stdClass)[4] 
        public 'long_name' => string 'Illinois' (length=8) 
        public 'short_name' => string 'IL' (length=2) 
        public 'types' => 
        array 
         0 => string 'administrative_area_level_1' (length=27) 
         1 => string 'political' (length=9) 
       2 => 
       object(stdClass)[5] 
        public 'long_name' => string '60631' (length=5) 
        public 'short_name' => string '60631' (length=5) 
        public 'types' => 
        array 
         0 => string 'postal_code' (length=11) 
      public 'geometry' => 
      object(stdClass)[6] 
       public 'location' => 
       object(stdClass)[7] 
        public 'lat' => float 41.985886 
        public 'lng' => float -87.790746 
       public 'location_type' => string 'ROOFTOP' (length=7) 
       public 'viewport' => 
       object(stdClass)[8] 
        public 'southwest' => 
        object(stdClass)[9] 
         public 'lat' => float 41.9827384 
         public 'lng' => float -87.7938936 
        public 'northeast' => 
        object(stdClass)[10] 
         public 'lat' => float 41.9890336 
         public 'lng' => float -87.7875984 

Answer 2

您使用json_decode。

例如爲：

$json_obj = json_decode($json); 
echo $json_obj->results[0]->geometry->location->lat; 

我們訪問結果陣列的第一個元素，然後通過幾何形狀，位置，和LAT屬性導航。你也可以使用關聯數組，但默認是一個對象。

Answer 3

問候，

我建議你閱讀json_decode文檔

<?php 
    $obj = json_decode($json); 
    $lat = $obj->results[0]->geometry->location->lat; 
    ?>