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Question

我正在嘗試使用Shapely中的'.within'函數...只是一個簡單的檢查，我無法解決這個語法錯誤。

我只是想重現我在docs.

代碼看到的例子是：

>>> from shapely.geometry import Point, LineString 

>>> LineString([(-9765787.9981184918000000 5488940.9749489054000000, -9748582.8016368076000000 5488402.1275707092000000)]).within(Point(-9763788.9782693591000000 5488878.3678984242000000)) 

返回：

>> Traceback ( File "<interactive input>", line 1 
    LineString([(-9765787.9981184918000000 5488940.9749489054000000, -9748582.8016368076000000 5488402.1275707092000000)]).within(Point(-9763788.9782693591000000 5488878.3678984242000000)) 
                   ^
SyntaxError: invalid syntax 

Answer 1

得到它。

>> LineString([(-9765787.9981184918000000,5488940.9749489054000000), (-9748582.8016368076000000,5488402.1275707092000000)]).within(Point(-9765787.9981184918000000,5488940.9749489054000000)) 

Answer 2

你有兩個選擇：

1）根據WKT字符串：

from shapely.wkt import loads as wkt_loads 
line = wkt_loads('LINESTRING(-9765787.9981184918000000 5488940.9749489054000000, -9748582.8016368076000000 5488402.1275707092000000)') 
point = wkt_loads('POINT(-9763788.9782693591000000 5488878.3678984242000000)') 

2）格式的格式正確的座標對列表作爲常規的Python浮動：

from shapely.geometry import Point, LineString 
line = LineString([(-9765787.9981184918000000, 5488940.9749489054000000), (-9748582.8016368076000000, 5488402.1275707092000000)]) 
point = Point(-9763788.9782693591000000, 5488878.3678984242000000) 

接下來，您將在測試中遇到一些浮點精度錯誤：

line.within(point) # False 
line.distance(point) # 7.765244949417793e-11 
line.distance(point) < 1e-8 # True 

我建議最後一個測試方法來確定點是否在線上。