爲什麼while循環在while循環內第一次迭代後沒有顯示結果？

我試圖通過newsfeed_id來獲取while循環中的註釋，但它在第一次迭代後不顯示任何結果。我print_r動態生成查詢其工作正常，但結果不顯示。爲什麼while循環在while循環內第一次迭代後沒有顯示結果？

$NewsfeedRes = array(); 
    $Newsfeed = "select * from `ws_newsfeed` where `nf_status` = 1"; 
    $NewsfeedQuery = mysqli_query($this->connection,$Newsfeed); 
    while($rowNews = mysqli_fetch_assoc($NewsfeedQuery)){ 
      $NewsfeedRes[] = $rowNews; 
      $PushComment = "SELECT cmt.`cmt_id`,cmt.`cmt_comment`,cmt.`date_added`, 
          us.`u_username`,us.`u_image` 
          FROM `ws_comments` AS cmt 
          LEFT JOIN `ws_user` AS us ON cmt.`u_id`=us.`u_id` 
          WHERE cmt.`cmt_target_id` = ".$rowNews['nf_id']." 
          AND cmt.`cmt_table_name`='ws_newsfeed'"; 
      //echo $PushComment; This giving me correct query 
      $PushCommentQuery = mysqli_query($this->connection,$PushComment); 
      while($rowPComment = mysqli_fetch_assoc($PushCommentQuery)){ 
       $NewsfeedRes['comments'] = $rowPComment; 
      } 
    } 
    $output = array(

     'NewsfeedRes' => $NewsfeedRes, 
    ); 
    echo json_encode($output, JSON_PRETTY_PRINT);

任何人都可以指導我哪裏我錯了，我可以解決這個問題。我會感激。謝謝

來源

2016-03-27 Mr. Developer

'$ newid = $ rowNews ['nf_id'];'並且在語句中使用''newsid''。 –

@MawiaHL我仍然只顯示一條記錄 –

假設nf_status = 1包含很多行。你不需要'$ NewsfeedRes [] = $ rowNews;'並選擇'cmt.cmt_comment as comments'。 –

每次循環訪問註釋循環時，都會重置$ NewsfeedRes ['comments']的值。您需要將$ rowPComment推入數組中。

如果你想$ rowNews和評論是在同一陣列嘗試：如果你想徵求意見和新聞提要嘗試一個單獨的陣列

while($rowNews = mysqli_fetch_assoc($NewsfeedQuery)){ 
     $PushComment = "SELECT cmt.`cmt_id`,cmt.`cmt_comment`,cmt.`date_added`,us.`u_username`,us.`u_image` FROM `ws_comments` AS cmt LEFT JOIN `ws_user` AS us ON cmt.`u_id`=us.`u_id` WHERE cmt.`cmt_target_id` = ".$rowNews['nf_id']." AND cmt.`cmt_table_name`='ws_newsfeed'"; 
     //echo $PushComment; This giving me correct query 
     $PushCommentQuery = mysqli_query($this->connection,$PushComment); 
     while($rowPComment = mysqli_fetch_assoc($PushCommentQuery)){ 
      $rowNews['comments'][] = $rowPComment; 
     } 
     $NewsfeedRes[] = $rowNews; 
}

：

while($rowNews = mysqli_fetch_assoc($NewsfeedQuery)){ 
     $NewsfeedRes["newsfeed"][] = $rowNews; 
     $PushComment = "SELECT cmt.`cmt_id`,cmt.`cmt_comment`,cmt.`date_added`,us.`u_username`,us.`u_image` FROM `ws_comments` AS cmt LEFT JOIN `ws_user` AS us ON cmt.`u_id`=us.`u_id` WHERE cmt.`cmt_target_id` = ".$rowNews['nf_id']." AND cmt.`cmt_table_name`='ws_newsfeed'"; 
     //echo $PushComment; This giving me correct query 
     $PushCommentQuery = mysqli_query($this->connection,$PushComment); 
     while($rowPComment = mysqli_fetch_assoc($PushCommentQuery)){ 
      $NewsfeedRes['comments'][] = $rowPComment; 
     } 

}

來源

2016-03-27 07:06:32 gmfm

試試這個。

while($rowNews = mysqli_fetch_assoc($NewsfeedQuery)){ 
      $newsid = $rowNews['nf_id']; 
      $PushComment = "SELECT cmt.`cmt_id`, cmt.`cmt_comment` as comments, 
          cmt.`date_added`, us.`u_username`,us.`u_image` 
          FROM `ws_comments` AS cmt 
          LEFT JOIN `ws_user` AS us ON cmt.`u_id`=us.`u_id` 
          WHERE cmt.`cmt_target_id` = '$newsid' 
          AND cmt.`cmt_table_name`='ws_newsfeed'";     
      $PushCommentQuery = mysqli_query($this->connection,$PushComment); 
      while($rowPComment = mysqli_fetch_assoc($PushCommentQuery)){ 
       $NewsfeedRes[] = $rowPComment['comments']; 
      } 
    }

來源

2016-03-27 07:11:09

爲什麼while循環在while循環內第一次迭代後沒有顯示結果？

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