迅速：改變數組的內容給我一個錯誤

我有此數組：迅速：改變數組的內容給我一個錯誤

var array = [[12,46,["a","b","c"],"nil",true,7,true],[10,40,["c","d","e"],"nil",true,7,true],[0,1,["z","l","w"],"hey",false,7,true]].

，當我試圖通過這個代碼更改數組布爾的最後一個布爾值：

array[0][6] = false

我得到這個錯誤「不能通過下標下標是隻能獲取數組」

來源

2016-06-29 Theilya

有趣。我認爲編譯器絆倒了某個地方。你只需要檢查陣列的類型來理解爲什麼：

var array = [ 
    [12,46,["a","b","c"],"nil",true,7,true], 
    [10,40,["c","d","e"],"nil",true,7,true], 
    [0,1,["z","l","w"],"hey",false,7,true] 
] 

print(array.dynamicType) // Array<NSArray> 
         // can't assign to the inner array since NSArray is immutable

給斯威夫特內型的暗示和它的作品

var array: [[AnyObject]] = [ 
    [12,46,["a","b","c"],"nil",true,7,true], 
    [10,40,["c","d","e"],"nil",true,7,true], 
    [0,1,["z","l","w"],"hey",false,7,true] 
] 

array[0][6] = false  // works

來源

2016-06-29 01:00:41

謝謝你已經工作了！ – Theilya

我不知道爲什麼Swift編譯器默認爲非Swift本機類型'NSArray'？ –

，您應該使用的元組數組來代替。使更好的代碼，執行更好，並且不依賴於Objective-C：

var array = [ 
    (12,46,["a","b","c"],"nil",true,7,true), 
    (10,40,["c","d","e"],"nil",true,7,true), 
    (0,1,["z","l","w"],"hey",false,7,true) 
] 

// Array has type [(Int, Int, [String], String, Bool, Int, Bool)] 

array[0].6 = false

來源

2016-06-29 01:08:01 Kametrixom

這澄清程序員的目的，特別是因爲外陣列的所有條目具有相同的結構（'Int'，'Int'，'[字符串]'，'String'，'Bool'，'Int'，'Bool'）。 –

迅速：改變數組的內容給我一個錯誤

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