在SQL Server中查找頂部行的SQL查詢

Question

在SQL Server中，我試圖獲得前5名工資。

我的工資就像

5000 
5000 
4500 
4500 
3000 
2000 
1000 
500 
400 

，我想獲得

5000 
5000 
4500 
4500 
3000 
2000 
1000 

Answer 1

如果你想獲得前5名不同的工資（不論相同金額可能有多少次出現），您需要使用DENSE_RANK()排名功能和CTE來實現這一目標：

DECLARE @salaries TABLE (salary DECIMAL(18,4)) 

INSERT INTO @salaries VALUES(5000) 
INSERT INTO @salaries VALUES(5000) 
INSERT INTO @salaries VALUES(4500) 
INSERT INTO @salaries VALUES(4500) 
INSERT INTO @salaries VALUES(3000) 
INSERT INTO @salaries VALUES(2000) 
INSERT INTO @salaries VALUES(1000) 
INSERT INTO @salaries VALUES(500) 
INSERT INTO @salaries VALUES(400) 

;WITH SalariesRanked AS 
(
    SELECT 
     Salary, 
     SalaryNumber = DENSE_RANK() OVER(ORDER BY Salary DESC) 
    FROM  
     @salaries 
) 
SELECT salary 
FROM SalariesRanked 
WHERE SalaryNumber <= 5 

這導致輸出這樣的：

salary 
5000.0000 
5000.0000 
4500.0000 
4500.0000 
3000.0000 
2000.0000 
1000.0000 

Answer 2

SELECT TOP 5 salary FROM your_table 
ORDER BY salary DESC 

Answer 3

看一看使用TOP (Transact-SQL)

Answer 4

select salary 
from 
    (
    select salary, 
      dense_rank() over(order by salary desc) as rn 
    from YourTable 
) as T 
where rn <= 5 

嘗試在SE-Data

Answer 5

SELECT TOP 5 Salary 
FROM [Table] 
GROUP BY Salary 
ORDER BY Salary DESC 

---

您需要組查詢，以避免重複小號alaries。