可以說我想要做$table = 'datatables_demo';
這樣的話我可以做select * from $table
變量?我怎樣才能做到這一點?我可以聲明在mysql命令行
LOG低於
mysql> select * from datatables_demo; +----+------------+-----------+-------------+--------+------------+--------+
| id | first_name | last_name | position | office | start_date | salary |
+----+------------+-----------+-------------+--------+------------+--------+
| 1 | Tiger | Nixon | Accountant | Tokyo | 2016-11-08 | 320800 |
| 2 | Garrett | Winters | Accountant2 | Tokyo | 2016-11-08 | 170750 |
| 3 | Ashton | Cox | Accountant3 | Tokyo | 2016-11-08 | 86000 |
| 4 | Cedric | Kelly | Accountant4 | Tokyo | 2016-11-08 | 433060 |
| 5 | Tiger5 | Nixon | Accountant | Tokyo | 2016-11-08 | 320800 |
+----+------------+-----------+-------------+--------+------------+--------+
5 rows in set (0.00 sec)
mysql> $table = 'datatables_demo';
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$table = 'datatables_demo'' at line 1
mysql> table = 'datatables_demo';
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'table = 'datatables_demo'' at line 1
mysql> var table varchar2(20)
-> ;
的可能的複製[如何聲明在MySQL變量?(http://stackoverflow.com/questions/11754781/how-to-declare-a-variable- in-mysql) – csmckelvey
那個笨蛋不會幫助解決這個問題。你需要一個存儲過程和一個concat和一個準備好的stmt在mysql中。總而言之,沒有太多投資回報的很多馬戲 – Drew
不可能從命令行 – Rahul