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我知道這個主題有一些問題需要回答,但我需要更具體的幫助,因爲這是我第一次嘗試這樣的事情。我試圖實現這些問題的答案,但仍然有錯誤。我需要將一個動態數量的序列化對象寫入文件,然後從該文件中讀取以檢索對象。我正在使用android的FYI。覆蓋writeStreamHeader()將序列化對象附加到單個文件
這是我寫()和重載writeStreamHeader():
//check and see if there is a file already created to hold patterns, if not, make one
//only created once or if file is deleted; append to it if it's already created
if(!new File(getFilesDir()+"/Patterns").exists())
{
try {
fos = new FileOutputStream(getFilesDir()+FILENAME, true);
out = new ObjectOutputStream(fos);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
else
{
try {
out = new AppendingObjectOutputStream(fos);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
//create a pattern of points. Max amount of Patterns is 100.
if(patternindex!=100)
{
Patterns[patternindex] = new Pattern(ActivePoints, name, xshift, yshift, scaling, rotation);
try {
//out.reset();
out.writeObject(Patterns[patternindex]); //write the object
//out.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
patternindex++;
dialog.dismiss();
}
public class AppendingObjectOutputStream extends ObjectOutputStream {
public AppendingObjectOutputStream(OutputStream out) throws IOException {
super(out);
}
@Override
protected void writeStreamHeader() throws IOException {
out.reset();
// do not write a header
}
}
我請檢查該文件是否存在(它,因爲我碰到這個代碼),然後我的writeObject()導致程序崩潰在創建「特殊」ObjectOutputStream後發生NULLPointerException異常。
這裏是我的反序列化/讀取:
String PatternNames[] = new String[2];
Pattern Patterns[] = new Pattern[2];
FileInputStream fis;
ObjectInputStream in;
try {
fis = new FileInputStream(getFilesDir()+"/Patterns");
in = new ObjectInputStream(fis);
for(int i=0;i<2;i++)//just trying to read 2 objects to start with
{
{
Patterns[i] = (Pattern) in.readObject();
PatternNames[i] = Patterns[i].getName();
}
}
in.close();
} catch (ClassNotFoundException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
任何幫助是極大的讚賞,因爲我已經花了很多時間相當試圖弄清楚這一點。我知道有些人已經完成了整個工作。作爲一個方面說明,我已經獲得序列化/反序列化處理一個對象保存到不同的文件,但這是最沒有用的,因爲我的項目需求。
發佈堆棧跟蹤。 – EJP 2012-08-05 09:49:14