7
我有這樣的代碼:Tastypie - 嵌套資源領域沒有找到
#api model
class VideoResource(ModelResource):
class Meta:
queryset = Video.objects.all()
include_resource_uri = False
resource_name = 'video'
authorization = DjangoAuthorization()
class QuestionResource(ModelResource):
user = fields.ToOneField(UserResource,'user',full=True)
video = fields.ForeignKey(VideoResource,'video',full=True)
class Meta:
queryset = Question.objects.all()
resource_name = 'question'
include_resource_uri = False
authorization = DjangoAuthorization()
def obj_create(self, bundle, request=None, **kwargs):
import json
temp = json.loads(request.body, object_hook=_decode_dict)
video = Video.objects.get(pk=temp['video'])
return super(QuestionResource, self).obj_create(bundle, request, user=request.user, video=video)
#model
class Question(models.Model):
text = models.CharField('Question',max_length=120)
created = models.DateTimeField(auto_now_add=True)
enabled = models.BooleanField(default=True)
flag = models.BooleanField(default=False)
allow_comments = models.BooleanField(default=True)
thumbnail_url = models.CharField(default='video.jpg',blank=True, null=True,max_length=200)
user = models.ForeignKey(User)
video = models.ForeignKey(Video)
def __unicode__(self):
return self.text;
class Video(models.Model):
created = models.DateTimeField(auto_now_add=True)
modified = models.DateTimeField(auto_now_add=True)
url = models.URLField(default="")
user = models.ForeignKey(User)
def __unicode__(self):
return str(self.pk) + ' > ' + self.status
問題是發送該對象時,我得到這個錯誤:
{"video":21,"text":"sadasds"}
「視頻」字段被給予非URI的數據,而不是 字典相似的,並且不具有'pk'屬性:21.
如果我評論這個li NE:
video = fields.ForeignKey(VideoResource,'video',full=True)
一切工作正常,但我不能得到這個信息(視頻) 問到/api/v1/questions/
我的問題的時候是:
- 我應該創建資源,一個帖子和另一個檢索 信息< - 這似乎不是一個很好的解決方案。 或
- 如何創建嵌套資源?我試圖按照 網絡http://django-tastypie.readthedocs.org/en/latest/cookbook.html#nested-resources 上的示例進行操作,但正如您所看到的,由於某些原因無法正常工作。
也許你的眼睛可以幫助我找到錯誤:) 謝謝!
你會提供如何發送請求嗎? – mhaligowski 2012-05-09 07:39:24