如何獲得並替換以下任務？

Question

我有一個像「test」的字符串模式：「abc/gef fhhff/fhrhr krerjr」，

我想以加號「test」開頭的行中的所有空格。如何使用正則表達式來做到這一點？

Answer 1

VB的淨嘗試

 Dim strCurrentLine as string = "test : abc/gef fhhff/fhrhr krerjr" 

     If UCase(strCurrentLine.ToString.StartsWith("TEST")) = True Then 
      strCurrentLine = Replace(strCurrentLine.ToString, " ", "Replace space with this text") 
     End If 

爲C＃嘗試

string strCurrentLine = "test : abc/gef fhhff/fhrhr krerjr"; 

    if (Strings.UCase(strCurrentLine.ToString().StartsWith("TEST")) == true) { 
     strCurrentLine = Strings.Replace(strCurrentLine.ToString(), " ", "Replace space with this text"); 
    } 

或去這裏的VB的正則表達式http://visualbasic.about.com/od/usingvbnet/a/RegExNET_2.htm

或去這裏爲C＃正則表達式http://oreilly.com/windows/archive/csharp-regular-expressions.html

Answer 2

在Perl中，你必須做一些事情，如：

use strict; 
use warnings; 

use 5.010; 

my $text = q|test : "abc/gef fhhff/fhrhr krerjr"|; 

#below is the regex that does the replace - \s is for whitespace class 
$text =~ s/\s/+/gmix if ($text =~ /^test/gmix); 

say "new text: $text";