我怎樣才能看到這個數組的結構？

Question

如何查看存儲在$response中的數組結構？我試過print_r()，但我無法在Chrome開發者中看到任何東西（獲得了php控制檯）。

function myajax_inputtitleSubmit_func() { 

    global $wpdb; 
$mp_country_table_info = $wpdb->prefix . 'countries '; //Good practice 
$mpcountrys = $wpdb->get_var("SELECT labour_cost FROM $mp_country_table_info WHERE id='2' "); 


     $nonce = $_POST['nextNonce']; 
    if (! wp_verify_nonce($nonce, 'myajax-next-nonce')) 
     die ('Busted!'); 

    $numwelds = isset($_POST['numberofwelds']) ? $_POST['numberofwelds'] : ''; 
$numconwelds = isset($_POST['numberofconwelds']) ? $_POST['numberofconwelds'] : ''; 
$fortot2 = 5; 
$fortot3 = 2; 

if (is_numeric($numwelds) && is_numeric($numconwelds)) 
{ 
    $total['tot1'] = $numwelds + $numconwelds + $mpcountrys ; 
    $total['tot2'] = $numwelds + $numconwelds + $fortot2 ; 
    $total['tot3'] = ($numwelds + $numconwelds) + $fortot2/$fortot3; 
    $response = json_encode($total); 
    print_r($total); // added line 
    header("Content-Type: application/json"); 
    echo $response; 
    exit; 
} 

UPDATE我已經試過以下&它不工作：

$total['tot1'] = $numwelds + $numconwelds + $mpcountrys ; 
    $total['tot2'] = $numwelds + $numconwelds + $fortot2 ; 
    $total['tot3'] = ($numwelds + $numconwelds) + $fortot2/$fortot3; 
    $response = json_encode($total); 
    header("Content-Type: application/json"); 
    echo $response; 
    exit; 
    //added bit 
    echo '<pre>'; 
    echo json_encode($response, JSON_PRETTY_PRINT); 
echo '</pre>'; 

更新兩個這似乎並不工作之一：

 $total['tot1'] = $numwelds + $numconwelds + $mpcountrys ; 
    $total['tot2'] = $numwelds + $numconwelds + $fortot2 ; 
    $total['tot3'] = ($numwelds + $numconwelds) + $fortot2/$fortot3; 
    echo '<pre>'; 
    echo json_encode($response, JSON_PRETTY_PRINT); 
echo '</pre>'; 
    header("Content-Type: application/json"); 
    echo $response; 
    exit; 

這是我第一次嘗試使用chrome php控制檯。我已'添加'它。我也通過查看這個網站http://php-console.com/instance/examples/#debug_vars確保我的工作正常。

更新3 - 所有的全功能

function myajax_inputtitleSubmit_func() { 

global $wpdb; 
$mp_country_table_info = $wpdb->prefix . 'countries '; //Good practice 
$mpcountrys = $wpdb->get_var("SELECT labour_cost FROM $mp_country_table_info WHERE id='2' "); 


     $nonce = $_POST['nextNonce']; 
    if (! wp_verify_nonce($nonce, 'myajax-next-nonce')) 
     die ('Busted!'); 

    $numwelds = isset($_POST['numberofwelds']) ? $_POST['numberofwelds'] : ''; 
$numconwelds = isset($_POST['numberofconwelds']) ? $_POST['numberofconwelds'] : ''; 
$fortot2 = 5; 
$fortot3 = 2; 

if (is_numeric($numwelds) && is_numeric($numconwelds)) 
{ 
    $total['tot1'] = $numwelds + $numconwelds + $mpcountrys ; 
    $total['tot2'] = $numwelds + $numconwelds + $fortot2 ; 
    $total['tot3'] = ($numwelds + $numconwelds) + $fortot2/$fortot3; 
    echo '<pre>'; 
    echo json_encode($total, JSON_PRETTY_PRINT); 
echo '</pre>'; 
    header("Content-Type: application/json"); 
    echo $response; 
    // exit; 
} 
} 

更新4 - 嘗試的var_dump - 也沒有工作

$total['tot1'] = $numwelds + $numconwelds + $mpcountrys ; 
$total['tot2'] = $numwelds + $numconwelds + $fortot2 ; 
$total['tot3'] = ($numwelds + $numconwelds) + $fortot2/$fortot3; 
$response = json_encode($total); 
header("Content-Type: application/json"); 
echo $response; 
exit; 
echo '<pre>'; 
var_dump($response); 
echo '</pre>'; 

Answer 1

試試這個從PHP

打印出JSON

echo '<pre>'; 
    echo json_encode($response, JSON_PRETTY_PRINT); 
echo '</pre>'; 

編輯

也許你在你的代碼

刪除所有打印/回聲/的var_dump和嘗試有一個以前的回聲某處此代碼：

ob_end_clean(); 

header('Content-Type: application/json'); 
$json = json_encode($total);   
echo $json; 

Answer 2

使用var_dump($response)，它提供了更好的輸出，當值是一個空值，如null或false。

Answer 3

就是這樣。

echo '<pre>'; 
var_dump($response); 
echo '</pre>';