簡單Python 3.2.2程序中的語法錯誤

Question

此代碼是來自python書籍的示例代碼。這是一個簡單的程序，用於輸入整數並顯示總和，總數和整數的平均值。但是，當我嘗試運行代碼時，在第18行冒號處收到語法錯誤。這段代碼對我來說看起來非常好。有任何想法嗎？

print("type integers, each followed by Enter; or just Enter to finish") 

total = 0 
count = 0 

while True: 
    line = input("integer: " 
    if line: 
     try: 
      number = int(line) 
     except ValueError as err: 
      print(err) 
      continue 
    total += number 
    count += 1 
    else: 
     break 
if count: 
    print("count=", count, "total =", total, "mean =", total/count) 

當我嘗試運行它，我得到一個錯誤：

File "./intproj.py", line 18 
    else: 
    ^
SyntaxError: invalid syntax 

我在Ubuntu 11.10使用IDLE作爲一個IDE使用Python 3.2.2

---

更新代碼：

print("type integers, each followed by Enter; or just Enter to finish") 

total = 0 
count = 0 

while True: 
    line = input("integer: ") 
    if line: 
     try: 
      number = int(line) 
     except ValueError as err: 
       print(err) 
       continue 
    total += number 
    count += 1 
    else: 
     break 
if count: 
    print("count=", count, "total =", total, "mean =", total/count) 

現在得到錯誤：

File "./intproj.py", line 18 
    else: 
    ^
SyntaxError: invalid syntax 

---

固定碼：

print("type integers, each followed by Enter; or just Enter to finish") 

total = 0 
count = 0 

while True: 
    line = input("integer: ") 
    if line: 
     try: 
      number = int(line) 
     except ValueError as err: 
       print(err) 
       continue 
     total += number 
     count += 1 
    else: 
     break 
if count: 
    print("count=", count, "total =", total, "mean =", total/count) 

謝謝！

Answer 1

您忘記關閉上一行的input()致電。

Answer 2

你需要一個右括號：

line = input("integer: ") 

Answer 3

9號線，似乎缺少了)

變化：

line = input("integer: " 

到

line = input("integer: ") 

的except行需要縮進以匹配try

和行：

total += number 
count += 1 

需要縮進以及否則，if和else語句不排隊。即代碼應該是這樣的：

print("type integers, each followed by Enter; or just Enter to finish") 

total = 0 
count = 0 

while True: 
    line = input("integer: ") 
    if line: 
     try: 
      number = int(line) 
     except ValueError as err: 
      print(err) 
      continue 
     total += number 
     count += 1 
    else: 
     break 
if count: 
    print("count=", count, "total =", total, "mean =", total/count) 

Answer 4

除了右括號問題，你行，說except ValueError as err:是不夠的縮進（其縮進級別應匹配的try語句）。這應該修復上面提到的錯誤18 else錯誤。

Answer 5

以total +=和count +=開頭的行需要以8個空格而不是4個空格開始。