Html.BeginForm不攜帶其當前PARAMS

Question

我有一個簡單的形式，看起來像這樣：

@using (Html.BeginForm("search", "home", new { param1 = "value1" }, FormMethod.Get)) 
{ 
    @Html.TextBox("Search", ViewBag.Search as string) 
    <button type="submit">Search </button> 
} 

HTML輸出如下：

<form action="/home/search?param1=value1" method="get"> 
    <input id="Search" name="Search" type="text" value=""> 
    <button type="submit">Search </button> 
</form> 

和我的控制器看起來是這樣的：

public ActionResult Search(string param1, string search) 
{ 
    // param1 returns as "null" 
    // search contains the value that was inside the textbox 
} 

有人知道我做錯了什麼？

Answer 1

Selman22建議正確的方法來完成這一點。不要將參數放在實際的URL上，而是將它們放在隱藏的窗體中。

@using (Html.BeginForm("search", "home", null, FormMethod.Get)) 
{ 
    <input type="hidden" name="param1" value="@ViewBag.Param1Value.ToString()" /> 
    @Html.TextBox("Search", ViewBag.Search as string) 
    <button type="submit">Search </button> 
} 

謝謝!!!!

Answer 2

一對夫婦的建議

• 用你的形式與POST
• 我總是建議使用強類型的視圖模型，它有很多好處

所以，你的代碼變得：

public class SearchViewModel { 
    public string param1 {get;set;} 
    public string search {get;set;} 
} 

[HttpPost] // <-- were you missing this before? 
public ActionResult Search(SearchViewModel model) 
{ 
    // access with model.param1 
} 

@model SearchViewModel 

@using (Html.BeginForm("search", "home", FormMethod.POST)) 
{ 
    @Html.HiddenFor(x=>x.param1) 
    @Html.TextBoxFor(x=>x.search) 
    <button type="submit">Search </button> 
}