我測試simperium與上次的python API:Simperium登錄無法驗證
從simperium.core進口驗證
# Global CONST
SIMPERIUM_APP_ID = "..."
SIMPERIUM_API_KEY = "..."
USER_NAME = '[email protected]'
USER_PWD = 'test'
def newUser(user, pwd):
auth = Auth(SIMPERIUM_APP_ID, SIMPERIUM_API_KEY)
print user, pwd
return auth.create(user, pwd)
def login(user, pwd):
auth = Auth(SIMPERIUM_APP_ID, SIMPERIUM_API_KEY)
print user, pwd
return auth.authorize(user, pwd)
def getApi(auth_token):
return Api(SIMPERIUM_APP_ID, auth_token)
print newUser(USER_NAME, USER_PWD):
token = login(USER_NAME, USER_PWD)
print token
print getApi(token)
用戶與有效的標記,但在登錄創建失敗,獲得auth.authorize
:
Traceback (most recent call last): File "/Users/**/Proyectos/**/testdata.py", line 22, in <module>
token = login(USER_NAME, USER_PWD) File "/Users/**/Proyectos/***/testdata.py", line 17, in login
return auth.authorize(user, pwd) File "/Library/Python/2.7/site-packages/simperium/core.py", line 59, in authorize
response = self._request(self.appname+'/authorize/', data) File "/Library/Python/2.7/site-packages/simperium/core.py", line 40, in
_request
response = urllib2.urlopen(request) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 400, in open
response = meth(req, response) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 513, in http_response
'http', request, response, code, msg, hdrs) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 438, in error
return self._call_chain(*args) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 372, in _call_chain
result = func(*args) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 521, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp) urllib2.HTTPError: HTTP Error 401: UNAUTHORIZED
是的,應用程序的「所有者」已經是同一應用程序的用戶。您可以使用我們的simperium用戶名和密碼登錄。 –