刪除行從數據庫中使用PHP /庫MySQLi

Question

請看看下面的循環：

$category = $mysqli->query('SELECT * FROM category'); 
    $divcounter = 0; 
    while($row = $category->fetch_assoc()) { 
     print '<div class="item col-xs-12 col-sm-6 col-md-3 col-lg-2">'; 
     print '<h4><a href="#tvb'.$row["id"].'" data-toggle="collapse" aria-expanded="false" aria-controls="tvb'.$row["id"].'" class="label label-success full-width"><span class="glyphicon glyphicon-triangle-right" aria-hidden="true"></span> '.$row["catname"].'</a></h4>'; 
     print '<div id="tvb'.$row["id"].'">'; 
     $link = $mysqli->query("SELECT * FROM links WHERE category='{$row["id"]}'"); 
     while($row = $link->fetch_assoc()) { 
      print '<li><a href="'.$row["url"].'">'.$row["name"].'</a>&nbsp;<span class="glyphicon glyphicon-remove text-danger" aria-hidden="true"></span></li>'; 
     } 
     $link->free(); 
     print '</div>'; 
     print '</div>'; 
     $divcounter++; 
     !($divcounter % 2) ? print '<div class="clearfix visible-sm-block"></div>' : ''; 
     !($divcounter % 4) ? print '<div class="clearfix visible-md-block"></div>' : ''; 
     !($divcounter % 6) ? print '<div class="clearfix visible-lg-block"></div>' : ''; 
    } 

請告訴我如何創建一個按鈕，坐在旁邊的李從資料庫中刪除，目前上市行？由於

<span class="glyphicon glyphicon-remove text-danger" aria-hidden="true"></span> 

這是delete.php的內容：

if(isset($_POST['catid']) and is_numeric($_POST['catid'])) 
     $id=$_POST['catid']; 
     $query = "DELETE FROM category WHERE id=(?)"; 
     $statement = $mysqli->prepare($query); 
     $statement->bind_param('i', $id); 
     $statement->execute(); 
     $statement->close(); 

Answer 1

 while($row = $link->fetch_assoc()) { 
     print '<li><a href="delete.php?id=' . $row["id"] . '" onclick="alert(\'Are you sure you want to delete this record?\')">delete</a><a href="'.$row["url"].'">'.$row["name"].'</a>&nbsp;<span class="glyphicon glyphicon-remove text-danger" aria-hidden="true"></span></li>'; 
    }