刪除括號內的文字

Question

嗨我是一個JavaScript的新手，所以我想知道你如何刪除括號內的文字&刪除括號？我也想刪除冒號前的單詞，然後用逗號替換括號，除了最後一個單詞。因此，例如，如果字符串包含：

language:chinese (29)parody:hyouka (73)character:fuyumi irisu (12)houtarou oreki (12)group:shuudan bouryoku (41)artist:murasaki syu (49)misc:schoolgirl (11)nakadashi (11)acting like a pet (6) 

然後輸出將成爲

chinese,hyouka,fuyumi irisu,houtarou oreki,shuudan bouryoku,murasaki syu,schoolgirl,nakadashi,acting like a pet 

我如何能做到這一點的JavaScript？這是代碼，它不工作

var str = "language:chinese (29)parody:hyouka (73)character:fuyumi irisu (12)houtarou oreki (12)group:shuudan bouryoku (41)artist:murasaki syu (49)misc:schoolgirl (11)nakadashi (11)acting like a pet (6)"; 

var tags = str.replace(/\s*\(.*?\)\s*/g, ',')); 
final = tags.replace(/.*(?=:)/i, ""); 
alert(final); 

Answer 1

使用[^）] +，表明這裏是開場後沒有結束括號：

var str = "language:chinese (29)parody:hyouka (73)character:fuyumi irisu (12)houtarou oreki (12)group:shuudan bouryoku (41)artist:murasaki syu (49)misc:schoolgirl (11)nakadashi (11)acting like a pet (6)"; 

var tags = str.replace(/\s?\([^\)]+\)/g, ',') 
       .replace(/[^:]+:([^,]+),/g,'$1,') 
              .replace(/,$/,''); 
alert(tags);​ 

即使是簡單的：

var tags = str.replace(/([^:]+:)?([^(]+)\s\([^\)]+\)/g,'$2,') 
       .replace(/,$/,'');