0
可以說我有類似以下如何獲取嵌入式文檔中的單個字段?
{
"_id" : 1,
"name" : "sue",
"age" : 19,
"type" : 1,
"status" : "P",
"favorites" : {
"artist" : "Picasso",
"food" : "pizza"
},
"finished" : [
17,
3
],
"badges" : [
"blue",
"black"
],
"points" : [
{
"points" : 85,
"bonus" : 20
},
{
"points" : 85,
"bonus" : 10
}
]
}
當我運行查詢像db.users.find({ favorites: { artist: "Picasso", food: "pizza" } }, { "favorites.food": 1 }).pretty()
我得到以下結果
{ "_id" : 1, "favorites" : { "food" : "pizza" } }
文檔是否有可能只拿到food
字段like
{ 「食品」: 「比薩」}
沒有favorites
關鍵?
我得到空文件,比如'{}' –
感謝的人,可以ü請告訴我diffference之間'aggregate'和'find'如果可能的話 –
@ N.HariHaraSudhan聚合類似於find(),但它允許您實現更復雜的查詢/文檔重新格式化;請參閱[聚合](https://docs.mongodb.com/manual/aggregation/)以獲取詳細信息 – felix