一次購買多個耗材

Question

我允許用戶一次購買多個耗材（同一類型）。我已經實現了下面的代碼：

- (void)purchaseMyProduct:(NSArray *) products { 
    if ([SKPaymentQueue canMakePayments]) {   
     for(SKProduct *product in products) { 
      SKPayment *payment = [SKPayment paymentWithProduct:product]; 
      [[SKPaymentQueue defaultQueue] addPayment:payment]; 
     } 

     [[SKPaymentQueue defaultQueue] addTransactionObserver:self]; 
    } 
    else { 
     UIAlertView *alertView = [[UIAlertView alloc]initWithTitle: 
           @"Purchases are disabled in your device" message:nil delegate: 
           self cancelButtonTitle:@"Ok" otherButtonTitles: nil]; 
    [alertView show]; 
} 

}

-(void)paymentQueue:(SKPaymentQueue *)queue updatedTransactions:(NSArray *)transactions { 
UIAlertView *alertView ; 
for (SKPaymentTransaction *transaction in transactions) { 
    switch (transaction.transactionState) { 

     case SKPaymentTransactionStatePurchasing: 
      NSLog(@"Purchasing"); 
      break; 

     case SKPaymentTransactionStatePurchased:         
      [[SKPaymentQueue defaultQueue] finishTransaction:transaction]; 
       [self 
      break; 

     default: 
      break; 
    } 
} 

}

但問題是，每個單獨的消耗品條目顯示一個單獨的提示，要求用戶確認購買。

IAP是否有可能一次購買同一類型的多種消耗品，並向用戶提供一個提示？

我曾經想過的一種邏輯是在商店中爲多種消耗品創建單獨的產品，例如，一個產品爲兩個，另一個爲三個消耗品。

請幫忙。

謝謝，

Answer 1

如果他們是相同類型，您應該使用數量字段。檢查SKPayment類參考。數量最大值爲10.

要創建數量大於1的SKPayment對象，請創建一個SKMutablePayment對象，調整其數量屬性，然後將其添加到付款隊列中。從文檔

實施例：

SKMutablePayment *myPayment = [SKMutablePayment paymentWithProduct: myProduct]; 
myPayment.quantity = 2; 
[[SKPaymentQueue defaultQueue] addPayment:myPayment];