0
我試着用幾種不同的方法重寫這個查詢,但沒有運氣。非常感謝這裏的幫助。無法解析查詢
function createWaterBodyDropDown(region) {
var query = "SELECT 'LAKE_NAME' FROM 1IfQgRAeKPbVJwEpAnqqpYlN8sgiPMg1VQ_RyArI WHERE 'REGION'=" + '"' + region + '"';
var queryText = encodeURIComponent(query);
var gvizQuery = new google.visualization.Query(
'http://www.google.com/fusiontables/gvizdata?tq=' + queryText);
//Send query and draw table with data in response
gvizQuery.send(function (response) {
var str;
var numRows = response.getDataTable().getNumberOfRows();
var numCols = response.getDataTable().getNumberOfColumns();
var name = [
'<label style="font-weight:bolder;font-size:16px">Water body: </label>' + '<select id="waterbody_menu" style="font-size:16px;" onchange="select_waterBody(this.options[this.selectedIndex].value);">' + '<option value="">--All--</option>'
];
for (var i = 0; i < numRows; i++) {
var val = response.getDataTable().getValue(i, 0);
name.push("<option value=" + "'" + val + "'" + ">" + val + "</option>");
}
name.push('</select>');
document.getElementById('waterBody_container').innerHTML = name.join('');
});
}
你把你列'LAKE_NAME'和'單引號內REGION',但在你的SQL雙引號內使用您的區域價值,讓您的SQL字符串結尾看起來像:'SELECT 'LAKE_NAME'FROM 1IfQgRAeKPbVJwEpAnqqpYlN8sgiPMg1VQ_RyArI WHERE'REGION'=「foobar」'這是故意的,還是會導致任何問題? – duncan
嗨,是的,這是故意的......我也試着寫這個查詢如下:var query =「SELECT LAKE_NAME FROM 1IfQgRAeKPbVJwEpAnqqpYlN8sgiPMg1VQ_RyArI WHERE REGION =」+ region; var query =「SELECT LAKE_NAME FROM 1IfQgRAeKPbVJwEpAnqqpYlN8sgiPMg1VQ_RyArI WHERE REGION =」+'「'+ region +'」';我猜測,goolge已經改變了他們的api。 – Michael