如何實現100毫秒睡眠的重試機制

Question

我想在一定的毫秒後執行這條指令。

我該如何做到這一點？

try { 
    // Get the typeface 
    MyApp.appTypeFace = Typeface.createFromAsset(getApplication().getAssets(), 
     MyApp.fontName); 
    Log.d("font","in try="+MyApp.fontName); 
    Log.d("font","type face="+MyApp.appTypeFace); 
} 

Answer 1

Handler handler; 

     handler=new Handler(); 
     Runnable notification = new Runnable() { 
      @Override 
      public void run() { 
       MyApp.appTypeFace = Typeface.createFromAsset(getApplication().getAssets(), 
     MyApp.fontName); 
    Log.d("font","in try="+MyApp.fontName); 
    Log.d("font","type face="+MyApp.appTypeFace); 

      } 
     }; 
     handler.postDelayed(notification,100); 

Answer 2

我通常使用CountDownTimer：

http://developer.android.com/reference/android/os/CountDownTimer.html

CountDownTimer timer = new CountDownTimer(100, 100) { 

    public void onTick(long millisUntilFinished) { 

    } 

    public void onFinish() { 
     //retry 
     //restart with timer.start(); 
    } 
    }.start(); 

但也有很多的替代品：的AsyncTask，線程，可運行。

例如：

Repeat a task with a time delay?

Answer 3

我會用Handler發佈一個Runnable，像這樣：

private Runnable task = new Runnable() { 
    public void run() { 
     // Execute your delayed code 
    } 
}; 

...

Handler handler = new Handler(); 
int millisDelay = 100; 
handler.postDelayed(task, millisDelay); 

的代碼將執行在postDelayed呼叫後100毫秒。