使用CSS和jQuery的移動菜單

Question

我在嘗試構建一個菜單，可以從右側滑入子項並允許用戶返回，如果需要的話。

雖然左側滑動元素有效，但後退按鈕不會刪除該類，儘管jQuery會告訴它如果<li>具有「返回」類。

我在邏輯中錯過了一些明顯的東西嗎？我也嘗試設置non-back元素有一個類，並設置jQuery僅在按下時運行，但仍然無效。

下面的代碼的筆至今：https://codepen.io/chops07876/pen/VbewZd

Answer 1

點擊事件被冒泡和觸發父李點擊。使用stopPropagation()可以防止出現這種情況，並將點擊事件限制爲您單擊的元素。 https://developer.mozilla.org/en-US/docs/Web/API/Event/stopPropagation

$('li').on('click',function(e) { 
 
    e.stopPropagation(); 
 
    if ($(this).hasClass('back')) { 
 
    $(this).parent().parent().parent().removeClass('hide'); 
 
    
 
    } else { 
 
    $(this).parent().addClass('hide'); 
 
    } 
 
});

a,abbr,acronym,address,applet,article,aside,audio,b,big,blockquote,body,canvas,caption,center,cite,code,dd,del,details,dfn,div,dl,dt,em,embed,fieldset,figcaption,figure,footer,form,h1,h2,h3,h4,h5,h6,header,hgroup,html,i,iframe,img,ins,kbd,label,legend,li,mark,menu,nav,object,ol,output,p,pre,q,ruby,s,samp,section,small,span,strike,strong,sub,summary,sup,table,tbody,td,tfoot,th,thead,time,tr,tt,u,ul,var,video{margin:0;padding:0;border:0;font:inherit;vertical-align:baseline}article,aside,details,figcaption,figure,footer,header,hgroup,menu,nav,section{display:block}body{line-height:1}blockquote,q{quotes:none}blockquote:after,blockquote:before,q:after,q:before{content:'';content:none}table{border-collapse:collapse;border-spacing:0} 
 

 
\t \t body { 
 
\t \t \t font-family: Arial, sans-serif; 
 
\t \t } 
 
\t \t 
 
\t \t ul { 
 
\t \t \t width: 100vw; 
 
\t \t \t position: absolute; 
 
\t \t \t background: #fff; 
 
\t \t \t left: 0; 
 
\t \t \t top: 0; 
 
\t \t \t list-style: none; 
 
\t \t \t -ms-transition: all .3s ease-in-out; 
 
\t \t \t -webkit-transition: all .3s ease-in-out; 
 
\t \t  -moz-transition: all .3s ease-in-out; 
 
\t \t  -o-transition: all .3s ease-in-out; 
 
\t \t  transition: all .3s ease-in-out; 
 
\t \t } 
 

 
\t \t ul.sub-menu { 
 
\t \t \t left: 100vw; 
 
\t \t } 
 

 
\t \t ul.show { 
 
\t \t \t left: 0; 
 
\t \t } 
 

 
\t \t ul.hide { 
 
\t \t \t left: -100vw; 
 
\t \t } 
 

 
\t \t ul.sub-menu.hide { 
 
\t \t \t left: 0; 
 
\t \t } 
 

 
\t \t ul li { 
 
\t \t \t padding: 10px; 
 
\t \t \t border-bottom: 1px solid #eee; 
 
\t \t \t cursor: pointer; 
 
\t \t } 
 

 
\t \t ul li.back { 
 
\t \t \t background: red; 
 
\t \t \t color: #fff; 
 
\t \t }

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 
 
<ul class="level-1"> 
 

 
    <li>Level One - Item One 
 

 
    <ul class="sub-menu level-2"> 
 

 
     <li class="back">Back</li> 
 

 
     <li>Level Two - Item One 
 

 
     <ul class="sub-menu level-3"> 
 

 
      <li class="back">Back</li> 
 

 
      <li>Level Three - Item One 
 

 
      <ul class="sub-menu level-4"> 
 

 
       <li class="back">Back</li> 
 

 
       <li>Level Four - Item One 
 

 
       <ul class="sub-menu level-5"> 
 

 
        <li class="back">Back</li> 
 

 
        <li>Level Five - Item One</li> 
 
        <li>Level Five - Item Two</li> 
 
        <li>Level Five - Item Three</li> 
 

 
       </ul> 
 

 
       </li> 
 
       <li>Level Four - Item Two</li> 
 
       <li>Level Four - Item Three</li> 
 

 
      </ul> 
 

 
      </li> 
 
      <li>Level Three - Item Two</li> 
 
      <li>Level Three - Item Three</li> 
 

 
     </ul> 
 

 
     </li> 
 
     <li>Level Two - Item Two</li> 
 
     <li>Level Two - Item Three</li> 
 

 
    </ul> 
 

 
    </li> 
 
    <li>Level One - Item Two</li> 
 
    <li>Level One - Item Three</li> 
 

 
</ul>

Answer 2

添加event.stopPropagation()到li的點擊

$('li').click(function() { 
event.stopPropagation(); 
if ($(this).hasClass('back')) { 
    $(this).parent().parent().parent().removeClass('hide'); 
} else { 
    $(this).parent().addClass('hide'); 
} 
}); 

我會使用closest()代替parent().parent().parent()

$(this).closest('.level-1').removeClass('hide');