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我寫了一個小程序,它會將選擇的圖像形成ImagePicker與此代碼(提取物),以twitpic:如何獲得特定用戶的最新形象的twitpic網站鏈接?
- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info {
[picker dismissModalViewControllerAnimated:YES];
UIImage * images = [info objectForKey:@"UIImagePickerControllerOriginalImage"];
NSData *imageData = UIImageJPEGRepresentation(images, 1);
NSURL *url = [NSURL URLWithString:@"http://twitpic.com/api/upload"];
NSString *username = @"Username";
NSString *password = @"HAHA";
[networkQueue cancelAllOperations];
[networkQueue setShowAccurateProgress:YES];
[networkQueue setUploadProgressDelegate:progressIndicator];
[networkQueue setDelegate:self];
// Now, set up the post data:
ASIFormDataRequest *request = [[[ASIFormDataRequest alloc] initWithURL:url] autorelease];
[request setData:imageData forKey:@"media"];
[request setPostValue:username forKey:@"username"];
[request setPostValue:password forKey:@"password"];
// Initiate the WebService request
progressIndicator.hidden = NO;
[networkQueue addOperation:request];
[networkQueue go];
}
正如你所看到的,我用ASIFormDataRequest發送了的狀態的請求和ASINetworkQueue上傳。我怎樣才能通過上傳的圖像(不是直接鏈接到圖像)鏈接到twitpic網站?
感謝您的幫助!
不是一個好主意把你的實際用戶名和密碼,就在這裏。我沒有足夠的代表來編輯它,不幸的是。 –
Ups ...這樣一個愚蠢的錯誤 – Flocked