1)I沒有解決在Renderer
isLeaf()
和Editor
不知何故
2)如果我把JScrollPane
與JTable
到Node
直接(不使用JPanel
作爲parent
)然後JTree View
未正確START_UP用於後呈現更多信息請看我的問題Put JTable in the JTree
import java.awt.*;
import javax.swing.*;
import javax.swing.table.DefaultTableModel;
import javax.swing.tree.*;
public class TreeWithTableRenderer extends JFrame {
private static final long serialVersionUID = 1L;
private JTree tree;
public TreeWithTableRenderer() {
DefaultMutableTreeNode AA1 = new DefaultMutableTreeNode("AA1");
DefaultMutableTreeNode AA2 = new DefaultMutableTreeNode("AA2");
DefaultMutableTreeNode A = new DefaultMutableTreeNode("A");
A.add(AA1);
A.add(AA2);
DefaultMutableTreeNode BB1 = new DefaultMutableTreeNode("BB1");
DefaultMutableTreeNode BB2 = new DefaultMutableTreeNode("BB2");
DefaultMutableTreeNode B = new DefaultMutableTreeNode("B");
B.add(BB1);
B.add(BB2);
DefaultMutableTreeNode CC1 = new DefaultMutableTreeNode("CC1");
DefaultMutableTreeNode CC2 = new DefaultMutableTreeNode("CC2");
DefaultMutableTreeNode C = new DefaultMutableTreeNode("C");
C.add(CC1);
C.add(CC2);
DefaultMutableTreeNode root = new DefaultMutableTreeNode("root");
root.add(A);
root.add(B);
root.add(C);
tree = new JTree(root);
tree.setCellRenderer(new MyTableInTreeCellRenderer());
tree.setRowHeight(0);
JScrollPane jsp = new JScrollPane(tree);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
add(jsp, BorderLayout.CENTER);
pack();
setLocationRelativeTo(null);
}
class MyTableInTreeCellRenderer extends JPanel implements TreeCellRenderer {
private static final long serialVersionUID = 1L;
private JTable table;
public MyTableInTreeCellRenderer() {
super(new BorderLayout());
table = new JTable();
JScrollPane scrollPane = new JScrollPane(table);
add(scrollPane);
}
public Component getTreeCellRendererComponent(JTree tree, Object value,
boolean selected, boolean expanded, boolean leaf, int row, boolean hasFocus) {
final String v = (String) ((DefaultMutableTreeNode) value).getUserObject();
table.setModel(new DefaultTableModel() {
private static final long serialVersionUID = 1L;
@Override
public int getRowCount() {
return 2;
}
@Override
public int getColumnCount() {
return 2;
}
@Override
public Object getValueAt(int row, int column) {
return v + ":" + row + ":" + column;
}
});
table.setPreferredScrollableViewportSize(table.getPreferredSize());
return this;
}
}
public static void main(String[] args) throws Exception {
SwingUtilities.invokeLater(new Runnable() {
public void run() {
new TreeWithTableRenderer().setVisible(true);
}
});
}
}
我還沒有測試過它,但爲什麼不應該這樣做呢。 API請求呈示器返回組件。而JTable是一個組件。在JTable編輯/選擇可能會更困難 – Robin 2012-01-12 17:01:06
@Robin但我的意思是視覺上,它是否合適?它是否有任何困難? – 2012-01-12 17:10:43
現在這很有趣。我的2美分:我覺得如果你的桌子很大,你的樹可能看起來很時髦。另外,我很好奇你是否真的能夠與桌子互動。它只是一張桌子的圖像? – user489041 2012-01-12 17:21:43