import java.util.Scanner;
public class NumAverage {
public static void main (String [] args)
{
//int a,b;
int[] numbers = new int [10];
Scanner numreader = new Scanner(System.in);
try
{
System.out.println("Enter 10 num");
for (int i = 0; i < numbers.length; i++)
numbers[i] = numreader.nextInt();
//numbers[i] = Integer.parseInt(s)
//for (int i = 0; i < numbers.length; i++)
//{
//sum += numbers[i];
//}
}
catch(NumberFormatException numfo)
{
System.out.println(numfo.getMessage() + "cannot be converted to integer");
}
}
}
我怎樣才能得到我已經被從鍵盤inputed到數組是parseInt函數,如果用戶嘗試輸入一個字符串,而不是整數parseInt函數在一個陣列
如何獲得只有有效的數字並丟棄字符串? – rendon