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Iam新的Swift中,我想將我的結構轉換爲參數與Alamofire 4發佈它。 請原諒我的英語不好。Swift 3結構參數Alamofire4
我的結構是在另一大類:
import Foundation
類structUser:NSObject的{
var myStructUser = [person]()
struct person {
var firstName : String
var lastName : String
var age: Int
init (firstName : String, lastName : String, age : Int) {
self.firstName = firstName
self.lastName = lastName
self.age = age
}
}
override init(){
myStructUser.append(person(firstName: "John", lastName: "Doe", age: 11))
myStructUser.append(person(firstName: "Richard", lastName: "Brauer", age : 22))
myStructUser.append(person(firstName: "Merrideth", lastName: "Lind", age : 55))
}
}
現在在主類我要發佈Alamofire,卻怎麼也我只轉換結構的名字和年齡?
import UIKit
類的ViewController:UIViewController的{
let classStructUser = structUser()
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
print(classStructUser.myStructUser)
}
func postJson(){
//need format [String : Any]
for item in classStructUser.myStructUser{
// var name = classStructUser.myStructUser.name
// var age = classStructUser.myStructUser.age
}
print(classStructUser.myStructUser)
/*here i need the Json in format:
{
"name":"John",
"age":11
}
{
"name":"Richard",
"age":22
}
{
"name":"Merrideth",
"age":55
}
an so on array.count
*/
}
}
另一個問題:
如何從VieControllerClass
訪問變量的結構(structUser)THX您的幫助!並請解釋完整的解決方案,因爲我想了解它是如何工作的。 Thx!
這就是全部?我怎樣才能選擇姓名和年齡? – silazzz
好的,謝謝!我會測試它!你能回答我的第二個問題嗎? – silazzz
查看更新的答案 – Bilal