從C＃中的某個單詞之前/之後的字符串中過濾值＃

Question

我有很長的字符串，它們是IMAP請求的響應，我想從中提取一些值。它通常被格式化爲「x someword」或「someword x」 - 如何讓某個詞（已知）得到x（可以是多個數字）？響應的每個「行」看起來像：

* x someword \r\n 

和我的字符串包含這幾行。提取期望值的最簡單方法是什麼？

示例： 爲 「* X WORD1 \ r \ n * Y WORD2 \ r \ n」 個，與WORD2作爲參數我想得Y

所有響應例如：

* FLAGS (\\Answered \\Flagged \\Draft \\Deleted \\Seen)\r\n* OK [PERMANENTFLAGS()] Flags permitted.\r\n* OK [UIDVALIDITY xxx] UIDs valid.\r\n* 3 EXISTS\r\n* 0 RECENT\r\n* OK [UIDNEXT x] Predicted next UID.\r\n. OK [READ-ONLY] INBOX selected. (Success)\r\n 

對於 「是否存在」 我想3

Answer 1

我會用正則表達式...這裏是你可以做什麼：

string myString = "* FLAGS (\\Answered \\Flagged \\Draft \\Deleted \\Seen)\r\n* OK [PERMANENTFLAGS()] Flags permitted.\r\n* OK [UIDVALIDITY 657136382] UIDs valid.\r\n* 3 EXISTS\r\n* 0 RECENT\r\n* OK [UIDNEXT 4] Predicted next UID.\r\n. OK [READ-ONLY] INBOX selected. (Success)\r\n"; 

string myWordToFind = "EXISTS"; 

string result = Regex.Match(myString, @"(?<MyNumber>\d+)\s*(" + Regex.Escape(myWordToFind) + ")", 
    RegexOptions.Compiled | RegexOptions.IgnoreCase) 
    .Groups["MyNumber"].Value; 

Answer 2

所以給出： X markerWord \ n \ rmarkerWordŸ

你想{X，Y}？ 如果是這樣，請嘗試先按行分割，然後再簡單地移除「markerWord」。

事情大致是這樣：

var result = input.Split(new[]{'\n', '\r'}).Select(line => line.Replace("markerWord", string.Empty); 

更新答案： 那好吧，我會用正則表達式。概念的簡單的證明，我敢肯定，你可以把它從這裏：

static string GetParam(string input, string param) { 
      var pattern = new Regex(@"[\\*](?<value>.+)" + param); 
      var split = input.Split(new[] { '\n', '\r' }, StringSplitOptions.RemoveEmptyEntries); 
      var line = split.SingleOrDefault(l => pattern.IsMatch(l)); 
      if(line != null) { 
       return pattern.Match(line).Groups["value"].Value.Trim(); 
      } 
      return null; 
     } 

Answer 3

class Class1 
{ 
    string str = "* FLAGS (\\Answered \\Flagged \\Draft \\Deleted \\Seen)\r\n* OK [PERMANENTFLAGS()] Flags permitted.\r\n* OK [UIDVALIDITY 657136382] UIDs valid.\r\n* 3 EXISTS\r\n* 0 RECENT\r\n* OK [UIDNEXT 4] Predicted next UID.\r\n. OK [READ-ONLY] INBOX selected. (Success)\r\n"; 

    public void FindString(string parm) 
    { 
     if (str.Contains(parm)) 
     { 
      string[] parts = str.Split('*'); 
      foreach (var item in parts) 
      { 
       if (item.Contains(parm)) 
       { 
        string[] values = item.Split(' '); 
        string value = values[1]; 
       } 
      } 
     } 
    } 

    static void Main(string[] args) 
    { 
     Class1 c = new Class1(); 
     c.FindString("EXISTS"); 
    } 
} 

Answer 4

您應該使用此

Regex r=new Regex(@"(?<value>\d+)\s*(?<keyword>EXISTS|RECENT)"); 

foreach (var match in r.Matches(source).OfType(Match)) { 
    var parameter=int.Parse(match.Groups["value"].Value); 
    switch (match.Groups["keyword"].Value) { 
    case "EXISTS": 
     doExists(parameter); 
     break; 
    case "RECENT": 
     doRecent(parameter); 
     break; 
    } 
} 

Answer 5

一個正則表達式，您可以使用下面的（希望，不言自明）代碼：

const string response =@" 
    * FLAGS (\\Answered \\Flagged \\Draft \\Deleted \\Seen) 
    * OK [PERMANENTFLAGS()] Flags permitted. 
    * OK [UIDVALIDITY 657136382] UIDs valid. 
    * 3 EXISTS 
    * 0 RECENT 
    * EXISTS 4  <------------------- another occurence of the word 
    * OK [UIDNEXT 4] Predicted next UID. 
    * OK [READ-ONLY] INBOX selected. (Success)"; 

    string word = "EXISTS"; 
    string pattern = 
     Regex.Escape(word) + // the word to find followed by... 
     @" 
     \s+   (?# one ore more space characters followed by...) 
     (?<num>\d+) (?# one or more digits.) 

     |   (?# Or) 

     (?<num>\d+) (?# one or more digits, then...) 
     \s+   (?# one ore more space characters followed by...)" 
     + Regex.Escape(word); // the word to find. 

    foreach (Match match in Regex.Matches(response, pattern, RegexOptions.Multiline | RegexOptions.IgnorePatternWhitespace)) 
    { 
     Console.WriteLine(match.Groups["num"]); 
    }