2015-10-04 49 views
0

我在寫jQuery代碼。但我現在有一個問題。當我編寫這些代碼時,我想關閉彈出窗口的可調整大小的選項。但事實並非如此。我能做什麼 ?Jquery popup可調整大小的參數

Jquery的代碼

<script type="text/javascript" language="javascript"> 
     <!-- 
     function popupfs(url) 
     { 
      alert($(window).width()); 
     params = 'top=0, left=0' 
      if($(window).width() < 1200){ 
       params += ', width='+(962)+', height='+(656); 
      }else if($(window).width() > 1200 && $(window).width() < 1550){ 
       params += ', width='+(1100)+', height='+(750); 
      }else if($(window).width() > 1550){ 
       params += ', width='+(1547)+', height='+(1055); 
      } 
     params += ', directories=no'; 
     params += ', location=no'; 
     params += ', menubar=no'; 
     params += ', resizable=no'; 
     newwin=window.open(url,'windowname4', params); 
     if (window.focus) {newwin.focus()} 
     return false; 
     }// --> 

     </script> 

HTML代碼

<body> 
     <div id="external" > 

     </div> 
     <a href="javascript: void(0)" onclick="popupfs('2/index.html')">Ekranın Ortasına Popup Açma</a> 
    </body> 

回答