打印當前值和未來值

Question

可能重複： Iterate a list as pair (current, next) in Python

雖然迭代名單，我想打印在列表中的當前項目，加上未來價值在列表中。

listOfStuff = [a,b,c,d,e] 
for item in listOfStuff: 
    print item, <nextItem> 

輸出將是：

a b 
b c 
c d 
d e 

Answer 1

最簡單的方法，我發現是：

a = ['a','b','c','d','e'] 

for i,nexti in zip(a,a[1::]): 
    print i,nexti 

Answer 2

listOfStuff = ['a','b','c','d','e'] 
for i, item in enumerate(listOfStuff[:-1]): 
    next_item = listOfStuff[i+1] 
    print item, next_item 

Answer 3

如何：

for i in range(1, len(listOfStuff)): 
    print listOfStuff[i - 1], listOfStuff[i] 

Answer 4

這可能做你想做的事：

def double_iter(iter): 
    a = next(iter) 
    for item in iter 
     yield (a, item) 
     a = item 

double_iter(original_iter)