Java中，嘗試捕獲後繼續

Question

當我運行程序100是由數字衆說紛紜，但一旦它到達0將出現一條消息，告訴用戶說100不能由0

分我如何獲得程序在錯誤之後繼續，並將其餘的數字除以100。

這是我當前的代碼：

public class testing { 
    int[] table; 
    int number; 

    public testing(int number) { 
     this.number = number; 
     table = new int[number]; 
    } 

    public static void main(String[] args) { 
     try { 
      int[] numbers = { 2, 3, 0, 4, 5 }; 
      testing division; 
      for (int i = 0; i < 5; i++) { 
       division = new testing(100/numbers[i]); 
       System.out.println("Answer is " + division.number); 
      } 
     } catch (Exception e) { 
      System.out.println("A number cannot be divided by 0"); 
     } 
    } 
} 

Answer 1

你可以簡單地做出更細粒度的規模try/catch語句 - 把它內 for循環。

for (int i = 0; i < 5; i++) { 
    try { 
     division = new testing(100/numbers[i]); 
     System.out.println("Answer is " + division.number); 
    } catch (ArithmeticException e) { // avoid catching with the overly broad Exception 
     System.out.println("A number cannot be divided by 0"); 
    } 
} 

我想盡量讓我的例外更具體，避免捕捉使用過度廣泛的Exception類，這裏使用ArithmeticException。

但更重要的是，我完全擺脫了try catch，並簡單地測試了0，完全避免了異常。

for (int i = 0; i < 5; i++) { 
    if (numbers[i] == 0) { 
     System.out.println("A number cannot be divided by 0"); 
    } else { 
     division = new testing(100/numbers[i]); 
     System.out.println("Answer is " + division.number); 
    } 
} 

Answer 2

看跌的try-catch中的內：

for (int i = 0; i < 5; i++) { 
    try{ 
    division = new testing(100/numbers[i]); 
    System.out.println("Answer is " + division.number); 
    } catch(Exception e){ 
     System.out.println("A number cannot be divided by 0"); 
    } 
    } 

Answer 3

更新代碼：增加了一個嘗試捕捉你的代碼：

public class testing { 

    int[] table; 
    int number; 

    public testing(int number) { 
    this.number = number; 
    table = new int[number]; 
    } 

    public static void main(String[] args) { 
    int[] numbers = { 2, 3, 0, 4, 5 }; 
    testing division; 

    for (int i = 0; i < 5; i++) { 
     try { 
     division = new testing(100/numbers[i]); 
     System.out.println("Answer is " + division.number); 
     } catch (Exception e) { 
     System.out.println("A number cannot be divided by 0"); 
     } 
    } 
    } 
} 

Answer 4

，如果出現異常，也沒有辦法去回來，但我們可以處理異常並與下一次迭代一起進行，或者在分割之前的條件下添加以下內容：

**if(numbers[i] != 0){** 
division = new testing(100/numbers[i]); 

或把try try catch在循環中。