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我想打開目錄並獲取該目錄中的所有文件名而不是子目錄。請幫我在此代碼readdir()試圖在無效的dirhandle DIR
#!/usr/bin/perl
use strict;
use warnings;
use Getopt::Long;
my $opt_section;
my $opt_content;
my $opt_help = 0;
&GetOptions (
"help" => \$opt_help,
"section:s" => \$opt_section,
"content:s" => \$opt_content,
);
if ($opt_help) {
print "USAGE: file.pl -section <section> -content <content> \n ";
exit;}
my $dir ="/home/priya/scripts/test/${opt_section}/${opt_content}/latest"; #base directory to look up for the files
print"$dir \n";
opendir(DIR, $dir) or die "Unable to read Directory : $!";
while (my $file = readdir(DIR)) {
#Only files not subdirectories
next unless (-f "$dir/$file");
#Use a regular expression to find files ending in .txt
$file =~ m/^${opt_section}.+txt$/i;
print "$file \n";
closedir(DIR);
}
exit 0;
我得到這個錯誤糾正在執行
它讀取第一個文件,並給它命名爲輸出,然後給這個錯誤
READDIR()嘗試在無效的dirhandle上DIR