Android Asynctask發佈到服務器錯誤

我是新來的android和開發一個android應用程序，當點擊一個按鈕時，將該項目發佈到服務器，將搜索項目（由用戶提供到EditText中）發佈到服務器。正在使用的AsyncTask class.I有誤差與findViewById（它是未定義）。我的問題是在哪裏放置的onclick方法和views.Here的referncing是代碼Android Asynctask發佈到服務器錯誤

public class Server_Post extends AsyncTask<String, Void, String> { 

    private static final int REGISTRATION_TIMEOUT = 3 * 1000; 
    private static final int WAIT_TIMEOUT = 30 * 1000; 
    private final HttpClient httpclient = new DefaultHttpClient(); 
    final HttpParams params = httpclient.getParams(); 
     HttpResponse response; 

     Button Submit = (Button) findViewById(R.id.submitButton); 
     EditText textvalue = (EditText)findViewById(R.id.searcheditText); 

     //Onclick Listener 
     Submit.setOnClickListener(onClickListener) 
     private OnClickListener onClickListener = new OnClickListener() { 
      @Override 
      public void onClick(final View v) { 
       switch(v.getId()){ 
        case R.id.submitButton: 
       break; 
      } 
     }; 

    protected void onPreExecute() { 
    //any code  

    } 

@Override 
protected String doInBackground(String... arg0) { 
    String URL = "url"; 
    String username = "abc"; 
    String password = "xyz"; 


    try { 
     HttpConnectionParams.setConnectionTimeout(params, REGISTRATION_TIMEOUT); 
     HttpConnectionParams.setSoTimeout(params, WAIT_TIMEOUT); 
     ConnManagerParams.setTimeout(params, WAIT_TIMEOUT); 

     HttpPost httpPost = new HttpPost(URL); 

     //Any other parameters you would like to set 
     List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2); 
     nameValuePairs.add(new BasicNameValuePair("username",username)); 
     nameValuePairs.add(new BasicNameValuePair("password",password)); 
     httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); 

     //Response from the Http Request 
     response = httpclient.execute(httpPost); 

     StatusLine statusLine = response.getStatusLine(); 
     //Check the Http Request for success 
     if(statusLine.getStatusCode() == HttpStatus.SC_OK){ 
      ByteArrayOutputStream out = new ByteArrayOutputStream(); 
      response.getEntity().writeTo(out); 
      out.close(); 

     } 
     else{ 
      //Closes the connection. 
      Log.w("HTTP1:",statusLine.getReasonPhrase()); 
      response.getEntity().getContent().close(); 
      throw new IOException(statusLine.getReasonPhrase()); 
     } 


    } catch (ClientProtocolException e) { 

    } catch (IOException e) { 

    }catch (Exception e) { 

    } 
    return null; 


} 

protected void onCancelled() { 

} 

protected void onPostExecute(String content) { 

} 


private void connecttopostdata() { 
    Server_Post task = new Server_Post(); 
    task.execute(textvalue.getText().toString()); 
    } 

}

響應是XML和我還希望在列表視圖上顯示響應。在此先感謝。

來源

2013-02-15 kkStep

您需要一個活動類的上下文才能從findviewbyid獲取按鈕。製作一個構造函數並從那裏找到你的觀點。像..

// give context from where you are calling your AsyncTask 
public Server_Post (Context context) 
{ 
    Button Submit = (Button) context.findViewById(R.id.submitButton); 
    EditText textvalue = (EditText)context.findViewById(R.id.searcheditText); 
}

來源

2013-02-15 14:07:49

這是一個解決方案，但IMO獲取數據的邏輯應該完全分開，並在不同的類中，並且使用'onPreExecute'方法中的參數傳遞的數據 – 2013-02-15 14:11:02

Android Asynctask發佈到服務器錯誤

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