修改JSON從MySQL和PHP兼容與黃包車圖

Question

我想通過PHP

它需要像這樣使用Rickshaw從MySQL顯示最後一個數據：

[ 
    { 
     "data": [ { "x": 1350995278, "y": 26.12 }, 
        { "x": 1350995276, "y": 26.19 }, 
        { "x": 1350995273, "y": 26.12 }, 
        { "x": 1350995271, "y": 26.19 }, 
        { "x": 1350995268, "y": 26.19 } ] 
    } 
] 

，但我的PHP與json_encode函數返回有點不同。我應該如何解決它？

PHP代碼：

while($row = mysql_fetch_assoc($select)) { 
     $r[] = $row; 
     $items[] = array('x' => $row['unixtime'], 'y' => $row['sensor']); 
    } 
    print json_encode($items); 

PHP OUTPUT：

[{"x":"1350996886","y":"26.06"}, 
{"x":"1350996884","y":"26.06"}, 
{"x":"1350996881","y":"26.06"}, 
{"x":"1350996879","y":"26.06"}, 
{"x":"1350996876","y":"26.06"}, 
{"x":"1350996874","y":"26.06"}, 
{"x":"1350996871","y":"26.06"}, 
{"x":"1350996869","y":"26.06"}, 
{"x":"1350996866","y":"26.06"}, 
{"x":"1350996864","y":"26.06"}] 

我不需要x後""：和Y：我是新來PHP，不知道如何找出， 請指教。

Answer 1

演員爲數字，如果你不希望他們被引用：

$items[] = array('x' => (float) $row['unixtime'], 'y' => (float) $row['sensor']);