爲什麼忽略if語句中的這個條件？

Question

這是我收到的錯誤：

>>> m.ask('please vend') 
Traceback (most recent call last): 
    File "/Users/Documents", line 196, in ask 
    getattr(self, 'vend') 
AttributeError: 'MissManners' object has no attribute 'vend' 

的VendingMachine級工作正常，但MissManners類沒有。我不知道爲什麼。

class VendingMachine: 
    """A vending machine that vends some product for some price. 

    >>> v = VendingMachine('candy', 10) 
    >>> v.vend() 
    'Machine is out of stock.' 
    >>> v.restock(2) 
    'Current candy stock: 2' 
    >>> v.vend() 
    'You must deposit $10 more.' 
    >>> v.deposit(7) 
    'Current balance: $7' 
    >>> v.vend() 
    'You must deposit $3 more.' 
    >>> v.deposit(5) 
    'Current balance: $12' 
    >>> v.vend() 
    'Here is your candy and $2 change.' 
    >>> v.deposit(10) 
    'Current balance: $10' 
    >>> v.vend() 
    'Here is your candy.' 
    >>> v.deposit(15) 
    'Machine is out of stock. Here is your $15.' 

    >>> w = VendingMachine('soda', 2) 
    >>> w.restock(3) 
    'Current soda stock: 3' 
    >>> w.deposit(2) 
    'Current balance: $2' 
    >>> w.vend() 
    'Here is your soda.' 
    """ 
    "*** YOUR CODE HERE ***" 
    def __init__(self, product, price): 
     self.itemName = product 
     self.cost = price 
     self.stock = 0 
     self.balance = 0 
    def vend(self): 
     if self.stock == 0: 
      print(" 'Machine is out of stock.' ") 
     elif self.balance < self.cost: 
      print(" 'You must deposit $" + str(self.cost - self.balance) + " more.'") 
     elif self.cost < self.balance: 
      print(" 'Here is your " + self.itemName + " and $" + str(self.balance - self.cost) + " change.'") 
      self.balance = 0 
      self.stock -= 1 
     else: 
      self.balance -= self.cost 
      self.stock -= 1 
      print("'Here is your " + self.itemName + ".'") 
    def restock(self, amount): 
     self.stock += amount 
     print("'Current " + self.itemName + " stock: " + str(self.stock) + "'") 
    def deposit(self, amount): 
     if self.stock == 0: 
      print("'Machine is out of stock. Here is your $" + str(amount) + ".'") 
     else: 
      self.balance += amount 
      print("'Current balance: $" + str(self.balance) + "'") 

class MissManners: 
    """A container class that only forward messages that say please. 

    >>> v = VendingMachine('teaspoon', 10) 
    >>> v.restock(2) 
    'Current teaspoon stock: 2' 

    >>> m = MissManners(v) 
    >>> m.ask('vend') 
    'You must learn to say please first.' 
    >>> m.ask('please vend') 
    'You must deposit $10 more.' 
    >>> m.ask('please deposit', 20) 
    'Current balance: $20' 
    >>> m.ask('now will you vend?') 
    'You must learn to say please first.' 
    >>> m.ask('please hand over a teaspoon') 
    'Thanks for asking, but I know not how to hand over a teaspoon.' 
    >>> m.ask('please vend') 
    'Here is your teaspoon and $10 change.'""" 
     def __init__(self, *args): 
      self.ask 

     def ask(self, *args): 
      result = '' 
      for arg in args: 
       if type(arg) == str: 
        result += arg 
       elif type(arg) == int: 
        balance = arg 
      if 'please' in result: 
       if 'deposit' in result: 
        self.deposit(balance) 
       elif 'vend' in result: 
        self.vend() 
      else: 
       return 'You must learn to say please first.' 

Answer 1

如果if語句前加上一個print result你會得到一個提示，那爲什麼發生這種情況，因爲它會輸出['p', 'l', 'e', 'a', 's', 'e', 'h', 'e', 'l', 'p']（假設你('please', 'help)的說法。請記住這個作爲打印語句是最快捷方式這種性質的調試問題（通常我去到更廣泛的測試之前）

這樣做的原因是使用了+ =運營商（result += arg） - 開關這一個append method（result.append(arg)），它應該工作

您的第二個問題請查看Calling a Class Method From Another Class Method - 因爲這提供了一個乾淨的方式來做你正在試圖做的事情VendingMachine

Answer 2

正如JGreenwell指出的，你得到這個的原因是因爲你的結果是一個列表。因此它收集所有字符以形成一個列表：

['p', 'l', 'e', 'a', 's', 'e'] 

而不是字符串'請'。在這裏，我提出了一個替代的方式來解決這個問題：初始化的結果字符串：

result = '' 

這樣，您將得到的結果你想