爲什麼name_Scenario [i]迭代每個單獨的char而不是數組中的每個字符串?簡單遍歷數組
var num_Scenarios;
var num_Features;
var name_Scenario = ["Login", "Users", "Yo", "Whatsup", "Diablo 3", "Junglr", "Microsoft", "Another", "Hi", "Anyone", "O", "Happy", "Stuff", "Sleep", "Account"];
var desc_Scenario;
function normalGrid() {
$("#tile-bank").remove();
$("#content").append("<div id=\"tile-bank\"></div>");
//Code where your data is received and you run addScenario() per interation
//filler global vars that your data will replace
num_Scenarios = 15;
num_Features = 20;
name_Scenario = "Login";
desc_Scenario = "This is a description.";
var add_to = $("#tile-bank");
for (var i = 0; i < num_Scenarios; i++) {
addScenario(add_to, num_Features, name_Scenario[i], desc_Scenario);
}
不,它不給你'h' – Ibu 2012-07-18 20:01:43
這與jQuery無關(因此編輯) – 2012-07-18 20:01:49
你是否嘗試過這一切?這是[小提琴](http://jsfiddle.net/6n5Gx/),它工作得很好,必須是你正在做的其他事情,將數組變成一個字符串。 – adeneo 2012-07-18 20:02:02