用「如果」給錯誤AS3的KeyboardEvent

Question

第1次使用的KeyboardEvent的事件監聽，我不能讓它工作：

下面是代碼：

stage.addEventListener(KeyboardEvent.KEY_DOWN, Cal); 

function Cal(event:KeyboardEvent):void 
{ 
    if (event.keyCode == Keyboard.ENTER) { 
     Calco(); 
    } 
} 

的錯誤，我得到的是：

場景1，圖層'操作'，第1幀，第95行1136：參數的數量不正確。預計1.

線94是如果線和95卡爾科的事情... 我沒有得到問題的地方。我有另一個可以正常工作的代碼示例，我用它作爲示例。

Answer 1

一些想法...和工作示例：

import flash.events.KeyboardEvent; 
import flash.ui.Keyboard; 


// #1 - use the proper variables/function names, upper and lower cases: 
// Classes: Xxxxxx 
// function : xxxxxx, xxxXxxxx 
// variables : xxxxXxxx, xxxxx 
// constants : XXXXXX 
// #2 - use the readable function name, no shotcuts... (just few advices); 

stage.addEventListener(KeyboardEvent.KEY_DOWN, handleKeyboardDown); 

function handleKeyboardDown( e :KeyboardEvent):void 
{ 
    // #3 - for keyboard events use switch instead... 

    // The error which was here is that the variable which parsed is named 'event' and you are using 'e', 
    // you need to use the same name as it being initialized 
    switch(e) 
    { 
     case Keyboard.ENTER : 

      // the error for your 'Calco()' function, is because 
      // function Calco (value.... expects for an variable. 
        // in this case this function does not required any variables 
      calculate(); 
      break; 
    } 
} 

function calculate():void 
{ 
    trace (this); 
}