如何提交表單，並隱藏和使用jquery

Question

顯示圖像和按鈕我使用JQuery

我有以下的html：

HTML代碼：

<div id="skywardsLogin" style="display: none;"> 
      <div class="formContainer" id="loginDetails"> 
       <form action="#" id="frmLogin" class="homeWidget"> 
        <table border="0" cellpadding="0" cellspacing="0"> 
         <tr> 
          <td class="formLabel" width="100"> 
           <label for="skywardsNumber" title="Skywards Number"> 
            Skywards Number</label></td> 
          <td> 
           <input class="formField" id="skywardsNumber" name="skywardsNumber" size="25" type="text" /></td> 
          <td class="formLink"> 
           <a class="iconHelpBox" href="#">Forgot number</a></td> 
         </tr> 
         <tr> 
          <td class="formLabel"> 
           <label for="password"> 
            Password</label></td> 
          <td> 
           <input class="formField" id="password" name="password" size="25" type="password" /></td> 
          <td class="formLink"> 
           <a class="iconHelpBox" href="#">Forgot password</a></td> 
         </tr> 
        </table> 
       </form> 
      </div> 
      <div class="horRuleWhite"> 
       <hr /> 
      </div> 
      <div class="continueBar"> 
       <div class="continueBarLeft"> 
        <p class="validateTips" style="color: Red"> 
        </p> 
       </div> 
       <div class="continueBarRightButton"> 
        <input alt="Log In" id="loginButton" src="system/images/form_buttons/button_log_in.gif" 
         title="Log In" type="image" /> 
        <div id="ajaxloading" style="display: none"> 
         <img align="absmiddle" src="system/images/spinner.gif" alt="Processing..."/>&nbsp;Processing... 
        </div> 
       </div> 
      </div> 
     </div> 

的JQuery代碼：

/ Dialog    
    $('#skywardsLoginLink').click(function(){ 
     $('#skywardsLogin').dialog({ 
      autoOpen: true, 
      width: 450, 
      modal: true, 
      title: 'Login to your Skywards Account' 
     }); 
     if($('#skywardsLogin').is(':visible')) { 
      hideSelect(); 
     } else { 
      showSelect(); 
     } 
    }); 

//Login Button Clicked 
$('#loginButton').click(function() 
{ 
    var bValid = true; 
    bValid = bValid && checkLength(skywardNo, "Skyward No", 3, 16); 
    bValid = bValid && checkLength(password, "password", 5, 16); 

    if (bValid) 
    {  
     $("#loginDetails > form").submit(); 
     allFields.val(""); 
     tips.text(""); 
    } 
}); 

//Submitting the form 
$("#loginDetails > form").submit(function() 
{ 
    //Hiding the Login button 
    ("#loginButton").hide(); 

    //Showing the ajax loading image 
    ("#ajaxloading").show(); 

    // 'this' refers to the current submitted form 
    var str = $(this).serialize(); 
    // -- Start AJAX Call -- 

    $.ajax({ 
     type: "POST", 
     url: "Login.aspx", // Send the login info to this page 
     data: str, 
     success: function(msg) 
     { 

      $("#loginDetails").ajaxComplete(function(event, request, settings){ 

      // Show 'Submit' Button 
      $('#loginButton').show(); 

      // Hide Gif Spinning Rotator 
      $('#ajaxloading').hide(); 

      if(msg == 'OK') // LOGIN OK? 
      { 
       $('a.modalCloseImg').hide(); 

       $(this).html(login_response); // Refers to 'status' 

      // After 3 seconds redirect the 
      //setTimeout('go_to_private_page()', 3000); 
     } 
     else // ERROR? 
     { 
      var login_response = msg; 
      $('#login_response').html(login_response); 
     } 

    }); 

    } 

    }); 

    // -- End AJAX Call -- 

    return false; 
});  

我試圖調用模態彈出對話框，它將驗證用戶名和密碼，如果全部是有效的形式#loginDetails>表格將被提交，表格正在提交，但其給出的錯誤（＃ loginButton」 .hide不低於上線的功能）

//Hiding the Login button 
    ("#loginButton").hide(); 

    //Showing the ajax loading image 
    ("#ajaxloading").show(); 

任何想法什麼都可以，因爲我們已經在我的HTML有兩個ID的原因。

謝謝。

Answer 1

錯過了這些行之前的$。

//Hiding the Login button 
    $("#loginButton").hide(); 

    //Showing the ajax loading image 
    $("#ajaxloading").show();