mysqli_fetch循環不工作

我有沒有工作的其他循環內循環，這是代碼：mysqli_fetch循環不工作

while($row = mysqli_fetch_array($result)) 
    { 
    echo "<tr>"; 
    echo "<td>" . $row['rowId'] . "</td>"; 
    echo "<td>" . $row['startDate'] . "</td>"; 
    echo "<td>" . $row['eventName'] . "</td>"; 
    echo "<td>" . $row['betName'] . "</td>"; 
    $string1 = "SELECT * FROM newCell WHERE rowId ='"; 
    $string2 = $row['rowId']."'"; 
    $result2 = $string1.$string2; 
    echo "<td>" . $result2 . "</td>"; 

    while($row2 = mysqli_fetch_array($result2)) 
    { 
     echo "<td>" . $row2['odds'] . "</td>"; 

     echo "<td>" . $row2['outcomeName'] . "</td>"; 
    } 
    echo "</tr>"; 
    }

當我直接查詢$結果2到BBDD第一個結果就顯示了三個結果，但代碼不會進入第二個LOOP。爲什麼？這裏有任何錯誤？

來源

2013-09-26 superTramp

您不在任何地方執行第二個循環的查詢。 –

告訴我們你的兩個查詢.. – Kalpit

你要求它循環一個'string'，而不是'mysqli'對象？ – MackieeE

while($row = mysqli_fetch_array($result)) 
    { 
    echo "<tr>"; 
    echo "<td>" . $row['rowId'] . "</td>"; 
    echo "<td>" . $row['startDate'] . "</td>"; 
    echo "<td>" . $row['eventName'] . "</td>"; 
    echo "<td>" . $row['betName'] . "</td>"; 
    $string1 = "SELECT * FROM newCell WHERE rowId ='"; 
    $string2 = $row['rowId']."'"; 
    $result2 = $string1.$string2; 
    echo "<td>" . $result2 . "</td>"; 

    $result2 = mysqli_query($connection, $result2); 

    while($row2 = mysqli_fetch_array($result2)) 
    { 
     echo "<td>" . $row2['odds'] . "</td>"; 

     echo "<td>" . $row2['outcomeName'] . "</td>"; 
    } 
    echo "</tr>"; 
    }

來源

2013-09-26 12:38:04 Mubin

用途：

$query = "SELECT ...."; 
$result2 = mysqli_query($db, $query); 

while($row2 = mysqli_fetch_array($result2)) 
{ 
     echo "<td>" . $row2['odds'] . "</td>"; 

     echo "<td>" . $row2['outcomeName'] . "</td>"; 
}

來源

2013-09-26 12:34:49 q0re

我覺得$ RESULT2應該是mysqli_query不僅僅只是查詢輸出。與MySQL類似。

也許你應該有這樣的事情

$result2 = mysqli_query($result2);

來源

2013-09-26 12:35:00

之前閱讀本How can I prevent SQL injection in PHP?話題。試後使用mysql_query()

來源

2013-09-26 12:35:18 RDK

嘗試這個

<?php 
while($row = mysqli_fetch_array($result)) 
    { 
    echo "<tr>"; 
    echo "<td>" . $row['rowId'] . "</td>"; 
    echo "<td>" . $row['startDate'] . "</td>"; 
    echo "<td>" . $row['eventName'] . "</td>"; 
    echo "<td>" . $row['betName'] . "</td>"; 
    $string1 = "SELECT * FROM newCell WHERE rowId ='"; 
    $string2 = $row['rowId']."'"; 
    $result2 = $string1.$string2; 
    echo "<td>" . $result2 . "</td>"; 
    $results = mysqli_query($db,$result2); 
    while($row2 = mysqli_fetch_array($results)) 
    { 
     echo "<td>" . $row2['odds'] . "</td>"; 

     echo "<td>" . $row['outcomeName'] . "</td>"; 
    } 
    echo "</tr>"; 
    } 
    ?>

來源

2013-09-26 12:35:42

之前獲取數據使用mysqli_query（）函數，然後運行mysqli_fetch_array（執行MySQL查詢）。如果您將結果計數爲$ count = mysqli_num_rows（$ query），並用if ... else管理您的代碼，那就太好了。

來源

2013-09-26 12:43:40

mysqli_fetch循環不工作

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