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我已經做了一個名爲OutlierInfo類如下拆分一個ArrayList和合並他們回來
public class OutlierInfo
{
public String month;
public int year;
public String id;
public int serialId;
public void setSerialId(int serialid)
{
serialId=serialid;
}
public void setMonth(String monthh)
{
month=monthh;
}
public void setYear(int yearr)
{
year=yearr;
}
public void setId(String idd)
{
id=idd;
}
}
廣告我Outlierinfo.I添加OutlierInfo的一些對象到ArrayList類型的ArrayList。現在我要做的是按照它們的SerialId對對象進行分組，然後將每個組的數組列表合併，然後合併組中的所有數組列表 這是我編寫的代碼，但它只是拋出錯誤，我不知道爲什麼。我需要一些幫助來找出爲什麼下面的代碼給出錯誤？
public class ArraylistSort
{
ArrayList<OutlierInfo> result = new ArrayList();
static ArrayList<ArrayList<OutlierInfo>> groupResult = new ArrayList<ArrayList<OutlierInfo>>();
String[] months = { "JAN", "FEB", "MAR", "APR" ,
"MAY", "JUN", "JUL", "AUG" ,
"SEP", "OCT", "NOV", "DECM"
};
int counter=0;
int count=0;
public ArraylistSort(){
for(int i=0;i<2;i++)
{
for(int j=0;j<4;j++)
{
int year=2000+j;
OutlierInfo o=setValues(i,months[j],year);
result.add(o);
System.out.println("result size"+result.size());
}
}
while(result.size()!=0)
{
OutlierInfo info1=new OutlierInfo();
info1=result.get(counter);
ArrayList<OutlierInfo> partialInfo=new ArrayList();
for(int j=1;j<count;j++)
{
OutlierInfo info2=new OutlierInfo();
info2=result.get(j);
if(info1.serialId==info2.serialId)
{
partialInfo.add(info2);
result.remove(info2);
}
}
partialInfo.add(info1);
System.out.println("partiainfosize"+partialInfo.size());
groupResult.add(partialInfo);
result.remove(info1);
System.out.println("r size "+result.size());
}
count=result.size();
}
private OutlierInfo setValues(int id,String month,int year)
{
OutlierInfo a = new OutlierInfo();
a.setSerialId(id);
a.setMonth(month);
a.setYear(year);
return a;
}
public static void main(String[] args)
{
ArraylistSort as=new ArraylistSort();
}
}
我得到以下錯誤：有人可以幫助我理解的錯誤沒有得到任何邏輯錯誤？
initial size 0
result size1
result size2
result size3
result size4
result size5
Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 6, Size: 6
result size6
result size7
result size8
at java.util.ArrayList.RangeCheck(ArrayList.java:547)
at java.util.ArrayList.get(ArrayList.java:322)
at STAnalysis.ArraylistSort.<init>(ArraylistSort.java:56)
at STAnalysis.ArraylistSort.main(ArraylistSort.java:98)
Java Result: 1
UPDATE
是我目前所面臨的是，當我實際上將對象添加到ArrayList中的錯誤「索引越界」所引發的最大的困惑！
UPDATE
我固定it.Turns我發現我搞砸了與curleybraces.My最終代碼
public class StAnamoliesSequencer
{
ArrayList<OutlierInfo> stAnomalies =new ArrayList();//arraylist of spatio-temporal outliers
ArrayList<ArrayList<OutlierInfo>> sequencedStAnomalies=new ArrayList<ArrayList<OutlierInfo>>();
int firstElement;
public StAnamoliesSequencer()
{
firstElement=0;
}
public ArrayList<ArrayList<OutlierInfo>> sequenceStAnomalies(ArrayList<OutlierInfo> sTanomalies)
{
int loopSizeDeterminer;//determines teh size of the inner loop and is dynamic.
for(int index=0;index<sTanomalies.size();index++)
{
OutlierInfo stOutlier=new OutlierInfo();
stOutlier=sTanomalies.get(index);
stAnomalies.add(index, stOutlier);
}
loopSizeDeterminer=stAnomalies.size();
while(stAnomalies.size()!=0)
{
OutlierInfo stOutlier1=new OutlierInfo();
ArrayList<OutlierInfo> tracker=new ArrayList();//arraylist that stores the grouped Outliers to be deleted later
stOutlier1=stAnomalies.get(firstElement);
ArrayList<OutlierInfo> similarOutlier=new ArrayList();//similaroutliers are kept in an arraylist
similarOutlier.add(stOutlier1);
tracker.add(stOutlier1);
for(int index=1;index<loopSizeDeterminer;index++)
{
OutlierInfo stOutlier2=new OutlierInfo();
stOutlier2=stAnomalies.get(index);
if(stOutlier1.serialId==stOutlier2.serialId)
{
similarOutlier.add(stOutlier2);
tracker.add(stOutlier2);
}
}
System.out.println("partiainfosize \t"+similarOutlier.size());
sequencedStAnomalies.add(similarOutlier);//adding arraylist of similar outliers to the arraylist of arraylist
for(int index=0;index<tracker.size();index++)
{
OutlierInfo groupedOutlier=new OutlierInfo();
groupedOutlier=tracker.get(index);
stAnomalies.remove(groupedOutlier);//grouped outliers are removed from original arraylist containing spatio-temporal outliers to reduce redundancy
}
System.out.println(" size "+stAnomalies.size());
loopSizeDeterminer=stAnomalies.size();
}
return sequencedStAnomalies;
}
}
我知道that.I我基本對象添加到動態此ArrayList因此陣列列表的大小正在增加，並且因爲我在這裏爲這個arralist添加了8個對象，所以它的大小必須是8，那麼爲什麼當程序嘗試訪問第6個對象時出現異常？酷我並不知道這樣的索引從1970 :) – user1720616