1
我想解析此Xml以獲得以下結果。該表的名稱是SchoolRecord如何將XML解析爲列
Name Answer
School name 87f6c8bf-cafc-40fb-a082-ca9d5bfaf1e0
Course 2f23e1cb-181e-4af2-a9ec-3dd68530d1d5
Father NULL
Mother NULL
我使用SQL Server 2012的這是我已經試過,但沒有奏效
1.
Select
S.userdefinedxml.value('(/ControlGroup/UserDefinedControls/Control/Name)[1]','varchar(max)') as Name,
S.userdefinedxml.value('(/ControlGroup/UserDefinedControls/Control/Answer)[1]','varchar(max)') as Answer
From SchoolRecord S
2.
Select
S.userdefinedxml.value('(School_Data/ControlGroup/UserDefinedControls/Control/Name)[1]','varchar(max)') as Name,
S.userdefinedxml.value('(School_Data/ControlGroup/UserDefinedControls/Control/Answer)[1]','varchar(max)') as Answer
From SchoolRecord S
3.
Select
S.userdefinedxml.value('(Data/School_Data/ControlGroup/UserDefinedControls/Control/Name)[1]','varchar(max)') as Name,
S.userdefinedxml.value('(Data/School_Data/ControlGroup/UserDefinedControls/Control/Answer)[1]','varchar(max)') as Answer
From SchoolRecord S
個
我的結果
Name Answer
NULL NULL
NULL NULL
NULL NULL
NULL NULL
我的XML:
<data>
<School_Data>
<ControlGroup>
<UserDefinedControls>
<Control>
<ControlType>FIND</ControlType>
<Name>School name</Name>
<Answer>87f6c8bf-cafc-40fb-a082-ca9d5bfaf1e0</Answer>
</Control>
</UserDefinedControls>
<UserDefinedControls>
<Control>
<ControlType>FIND</ControlType>
<Name>Course</Name>
<Answer>2f23e1cb-181e-4af2-a9ec-3dd68530d1d5</Answer>
</Control>
</UserDefinedControls>
<UserDefinedControls>
<Control>
<ControlType>FIND</ControlType>
<Name>Father</Name>
<Answer />
</Control>
</UserDefinedControls>
<UserDefinedControls>
<Control>
<ControlType>FIND</ControlType>
<Name>Mother</Name>
<Answer />
</Control>
</UserDefinedControls>
</ControlGroup>
</School_Data>
</data>
XML區分大小寫,因此您可以嘗試'data'而不是'Data'。例如'S.userdefinedxml.value('(data/School_Data/ControlGroup/UserDefinedControls/Control/Name)[1]','varchar(max)')as Name,' – Yuck 2014-10-31 22:43:59