MySQL查詢（LINK門票，員工，貓，評論）使用JOIN

門票

tic_id,  
tic_cat  
tic_priority 
tic_cus  
tic_date  
tic_title  
tic_msg  
tic_files  
tic_emp  
tic_moved  
tic_statue 
tic_rate

員工

emp_id  
emp_name  
emp_username 
emp_password 
emp_cat  
emp_special 
emp_lastlogin 
emp_session 
emp_code  
emp_statue 
emp_master 
emp_ip

貓

cat_id  
cat_type  
cat_name  
cat_statue 
cat_delete 
cat_date  
cat_ip  
cat_options

評論

com_id  
    tic_id  
    cus_id  
    emp_id  
    com_msg  
    com_time 
    com_ip  
    com_statue

而我需要的結果作爲

tic_id | tic_cat | cat_name | tic_title | tic_statue | tic_priority | tic_msg | emp_name | comments_row | last_comment |

我有這樣的查詢，但我有2個問題

查詢

SELECT 
     tickets.tic_id 
     ,tickets.tic_cat 
     ,cats.cat_name 
     ,tickets.tic_title 
     ,tic_statue 
     ,tic_priority 
     ,tickets.tic_msg 
     ,employee.emp_name 
     ,count(comments.com_id) 
     ,(SELECT comments.com_msg 
      from comments 
       order by com_id DESC limit 1) 
      AS last_comment 
     FROM tickets 
     LEFT JOIN employee 
        on (tickets.tic_emp = employee.emp_id) 
     LEFT join cats 
        on (tickets.tic_cat = cats.cat_id) 
     LEFT JOIN comments 
        on(tickets.tic_id = comments.tic_id) 

    WHERE tic_cus=2 /* 2 -> This Is Customer Id */ 
    GROUP BY comments.tic_id

個

我的問題，是

我有3個導致數據庫以客戶號2 - >只顯示2個結果

我想最後的評論 - > 2的結果具有相同的最後一個註釋

如何我能做到這一點查詢帶有OUT這2個錯誤

編輯帖子後新建查詢

問題二號解決使用這曲兒Ÿ

SELECT 
     tickets.tic_id 
     ,tickets.tic_cat 
     ,cats.cat_name 
     ,tickets.tic_title 
     ,tic_statue 
     ,tic_priority 
     ,tickets.tic_msg 
     ,employee.emp_name 
     ,count(comments.com_id) 
     ,(SELECT comments.com_msg 
      from comments 
       WHERE tickets.tic_id = comments.tic_id 
       order by com_id DESC limit 1) 
      AS last_comment 
     FROM tickets 
     LEFT JOIN employee 
        on (tickets.tic_emp = employee.emp_id) 
     LEFT join cats 
        on (tickets.tic_cat = cats.cat_id) 
     LEFT JOIN comments 
        on(tickets.tic_id = comments.tic_id) 

    WHERE tic_cus=2 
    GROUP BY comments.tic_id

解決

SELECT 
     tickets.tic_id 
     ,tickets.tic_cat 
     ,cats.cat_name 
     ,tickets.tic_title 
     ,tic_statue 
     ,tic_priority 
     ,tickets.tic_msg 
     ,employee.emp_name 
     ,count(comments.com_id) 
     ,(SELECT comments.com_msg 
      from comments 
       WHERE tickets.tic_id = comments.tic_id 
       order by com_id DESC limit 1) 
      AS last_comment 
     FROM tickets 
     LEFT JOIN employee 
        on (tickets.tic_emp = employee.emp_id) 
     LEFT join cats 
        on (tickets.tic_cat = cats.cat_id) 
     LEFT JOIN comments 
        on(tickets.tic_id = comments.tic_id) 

    WHERE tic_cus=2 
    GROUP BY tickets.tic_id

來源

2011-11-15 Mona Abdelmajeed

@Gordon：請注意，您刪除內容OP與上次編輯。 – mellamokb

@mellamokb是的，我可能在OP編輯之前查看了第一個版本，感謝您閱讀它。 – Gordon

1）你能告訴這些表中的一些數據來證明？換句話說，你怎麼知道你應該有三條記錄？ select * from tickets where tic_cus = 2本身是否返回3條記錄？

2）您需要按票據過濾評論子查詢。我也建議有以及在子查詢的評論數和乾脆離開了GROUP BY：

,(select count(comments.com_id) 
    from comments 
    where comments.tic_id = tickets.tic_id) as comment_count 

,(select comments.com_msg 
    from comments 
    where comments.tic_id = tickets.tic_id 
      ^^^^^^^ filter by ticket so not last of ALL comments 
order by com_id DESC limit 1) as last_comment

來源

2011-11-15 14:17:28 mellamokb

謝謝@mellamokb，問題解決了，看到我的帖子後編輯:) –

您的查詢幫助我找到問題我是羣組comment_row但我應該組ticket_tic_id :) –

MySQL查詢（LINK門票，員工，貓，評論）使用JOIN

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