傳遞參數與多個對象

Question

所以我想要做的是傳入一個對象列表，但我有許多不同的。 （劍，胸鎧等）。我怎樣才能將多個對象傳遞給參數？

ListToSave = testObject.ChestPlateList;下面的部分是我想要傳遞對象列表的部分。

public void DeserializeFromXML(List<ChestPlate> ListToSave, string filepath) 
     { 
      XmlSerializer deserializer = new XmlSerializer(typeof(GameObjectData)); 
      FileStream fs = new FileStream(filepath, FileMode.Open); 
      XmlReader reader = new XmlTextReader(fs); 

      if (!reader.EOF) 
      { 
       GameObjectData testObject = (GameObjectData)deserializer.Deserialize(reader); 
       ListToSave = testObject.ChestPlateList; 
       Console.WriteLine("{0}", testObject.ChestPlateList);    
      }   
     } 

Answer 1

試試這個（未經測試）

public void SerializeToXML(GameObjectData theData, string filepath) 
{ 
    XmlSerializer serializer = new XmlSerializer(typeof(theData)); 
    TextWriter writer = new StreamWriter(filepath); 
    serializer.Serialize(writer, ListToSave); 
} 

和

public GameObjectData DeserializeFromXML(string filepath) 
{ 
    GameObjectData result = null; 
    XmlSerializer deserializer = new XmlSerializer(typeof(GameObjectData)); 
    FileStream fs = new FileStream(filepath, FileMode.Open); 
    XmlReader reader = new XmlTextReader(fs); 

    if (!reader.EOF) 
    { 
     result = (List<GameObject>)deserializer.Deserialize(reader); 

     Console.WriteLine("{0}", result.ChestPlateList);    
    } 
    return result;  
}