我有一個用於顯示數據的gridView。 GridView的表中有一個是被稱爲創建列,此列包含用戶,我從用戶表得到ID的。基本上,此列會顯示這樣的數據作爲整數(ID):Yii2 Gridview過濾基於varchar作爲輸入值的Int數據類型的列
但我給自己定這樣的代碼來顯示ID的用戶名:
[
'attribute' => 'created_by',
'format' => 'raw',
'value' => function ($data) {
$modelUser = Users::find()->where(['id' => $data->created_by])->one();
$nama = $modelUser->username;
return $nama;
},
'vAlign' => 'middle',
'hAlign' => 'center',
],
結果:
gridView有過濾器列,我試圖根據插入的值過濾數據。我想輸入的用戶名作爲過濾值,但它給出錯誤信息「通過創建必須是整數」,像這樣:
我如何可以使用過濾該列用戶名(VARCHAR)?
感謝
更新
這是我searchModel.php
<?php
namespace app\search;
use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\Product;
/**
* ProductSearch represents the model behind the search form of `app\models\Product`.
*/
class ProductSearch extends Product {
/**
* @inheritdoc
*/
public function rules() {
return [
[['productId', 'userId', 'parentId', 'created_by'], 'integer'],
[['date', 'created_at', 'name', 'address'], 'safe'],
[['price'], 'number'],
];
}
/**
* @inheritdoc
*/
public function scenarios() {
// bypass scenarios() implementation in the parent class
return Model::scenarios();
}
/**
* Creates data provider instance with search query applied
*
* @param array $params
*
* @return ActiveDataProvider
*/
public function search($params) {
$query = Product::find();
// add conditions that should always apply here
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
return $dataProvider;
}
// grid filtering conditions
$query->andFilterWhere([
'productId' => $this->productId,
'price' => $this->price,
'created_at' => $this->created_at,
'created_by' => $this->created_by,
]);
$query->andFilterWhere(['MONTH(date)' => $this->date])
->andFilterWhere(['like', 'name', $this->name])
->andFilterWhere(['like', 'address', $this->address]);
return $dataProvider;
}
}
這是工作,但我必須首先創建模型關係。因爲我的表格兩者之間沒有關係。感謝:D – Blackjack
但是,如果我有另一列,例如列**電子郵件**,我該如何才能使其工作。該列電子郵件基於用戶ID,就像創建者一樣。我嘗試使用相同的關係,或者只是使用預覽關係。但它不起作用。 – Blackjack
@Blackjack。你想通過電子郵件或用戶名過濾用戶嗎?說明。 –