2017-04-15 114 views
1

我有一種情況,我想根據某些單詞的出現次數從mongodb中定義我自己的函數對數據進行排序。在貓鼬上定義自定義排序功能

例如,我有這樣的模式:

const RecipeSchema = mongoose.Schema({ 
    Title: { type: String }, 
    Content: { type: String }, 
    PublishDate: { type: Date }, 
}); 

這些值:

Title: 'Chocolate Cake', 
Title: 'Naked Cake', 
Title: 'Fruit Cake', 
Title: 'Beef' 

所以,當我查詢 「裸蛋糕」,我想這樣的

結果
Title: 'Naked Cake', // 1, because have the two words 
Title: 'Chocolate Cake', // 2 because have just one word 
Title: 'Fruit Cake', // 3 because have just one word 
// beef has no match word 

今天我有這個查詢功能:

Recipe 
    .find() 
    .where({ Title: GetQueryExpression(value)}) 
    .sort({ PublishDate: -1 }) 
    .exec(callback); 

而且GetQueryExpression功能是:

function GetQueryExpression(value){ 
    var terms = value.split(' '); 
    var regexString = ""; 

    for (var i = 0; i < terms.length; i++) 
     regexString += terms[i] + '|'; 

    regexString = regexString.substr(0, regexString.length - 2); 
    var result = new RegExp(regexString, 'ig'); 

    return result; 
} 

也有人有一些想法如何實現這一排序,couting的話!?發生

回答

2

使用Text Search執行不區分大小寫的文本搜索,它使用分詞器&干擾算法有效地查找文本。您必須定義一個text索引,並在集合的text索引上執行搜索:

var mongoose = require('mongoose'); 

var db = mongoose.createConnection("mongodb://localhost:27017/testDB"); 

var RecipeSchema = mongoose.Schema({ 
    Title: { type: String }, 
    Content: { type: String }, 
    PublishDate: { type: Date }, 
}); 

RecipeSchema.index({ name: 'text', 'Title': 'text' }); 

var Recipe = db.model('Recipe', RecipeSchema); 

Recipe.find({ $text: { $search: "naked cake" } }, function(err, res) { 
    console.log(res); 
});