在Python中使用讀取文本文件創建一個使用字符串的列表

Question

我想在python中使用文本文件中的單詞而不是直接寫入python文件中的單詞（在這種情況下，代碼完美地工作）製作混雜遊戲。但是，當我想導入他們，我得到這個列表：

[['amazement', ' awe', ' bombshell', ' curiosity', ' incredulity', '\r\n'], ['godsend', ' marvel', ' portent', ' prodigy', ' revelation', '\r\n'], ['stupefaction', ' unforeseen', ' wonder', ' shock', ' rarity', '\r\n'], ['miracle', ' abruptness', ' astonishment\r\n']] 

我想的話在一個單一的列表進行排序，例如：

["amazement", "awe", "bombshell"...] 

這是我的Python代碼：

import random 

#Welcome the player 
print(""" 
    Welcome to Word Jumble. 
     Unscramble the letters to make a word. 
""") 


filename = "words/amazement_words.txt" 

lst = [] 
with open(filename) as afile: 
    for i in afile: 
     i=i.split(",") 
     lst.append(i) 
print(lst) 

word = random.choice(lst) 
theWord = word 

jumble = "" 
while(len(word)>0): 
    position = random.randrange(len(word)) 
    jumble+=word[position] 
    word=word[:position]+word[position+1:] 
print("The jumble word is: {}".format(jumble)) 

#Getting player's guess 
guess = input("Enter your guess: ") 

#congratulate the player 
if(guess==theWord): 
    print("Congratulations! You guessed it") 
else: 
    print ("Sorry, wrong guess.") 

input("Thanks for playing. Press the enter key to exit.") 

我有文字的文本文件：

amazement, awe, bombshell, curiosity, incredulity, 
    godsend, marvel, portent, prodigy, revelation, 
    stupefaction, unforeseen, wonder, shock, rarity, 
    miracle, abruptness, astonishment 

謝謝你的幫助和任何建議！

Answer 1

準一班輪做它：

with open("list_of_words.txt") as f: 
    the_list = sorted(word.strip(",") for line in f for word in line.split()) 

print(the_list) 

• 使用在GEN-理解雙for
對空間
• 分裂是絕招：它擺脫了行終止字符和多重的空間。然後，使用strip()擺脫逗號。
• 上所產生的發電機理解應用sorted

結果：

['abruptness', 'amazement', 'astonishment', 'awe', 'bombshell', 'curiosity', 'godsend', 'incredulity', 'marvel', 'miracle', 'portent', 'prodigy', 'rarity', 'revelation', 'shock', 'stupefaction', 'unforeseen', 'wonder'] 

只有這種快速方法的缺點是，如果2個字只用逗號隔開，它會發出2個字作爲-is。

在這後者的情況下，只是在這樣的gencomp添加for執行分裂根據逗號和丟棄空的結果字符串（if word）：

with open("list_of_words.txt") as f: 
    the_list = sorted(word for line in f for word_commas in line.split() for word in word_commas.split(",") if word) 

print(the_list) 

或者在後者的情況下，也許使用正則表達式分割更好（我們也需要放棄空字符串）。拆分表達式爲空白或逗號。

import re 

with open("list_of_words.txt") as f: 
    the_list = sorted(word for line in f for word in re.split(r"\s+|,",line) if word) 

Answer 2

str.split（）生成一個列表，所以如果將它附加到結果中，您將得到一個列表列表。 一個解決方案是串聯的2列表（+）

可以拆分它

Answer 3

使用

lst.extend(i) 

代替

之前擺脫 '\ r \ n' 的通過剝離我

lst.append(i) 

split返回一個列表，並且每次列出一個列表。使用擴展代替將解決您的問題。

Answer 4

請嘗試以下代碼：

import random 

#Welcome the player 
print(""" 
    Welcome to Word Jumble. 
     Unscramble the letters to make a word. 
""") 

name = " My name " 

filename = "words/amazement_words.txt" 

lst = [] 
file = open(filename, 'r') 
data = file.readlines() 

another_lst = [] 
for line in data: 
    lst.append(line.strip().split(',')) 
print(lst) 
for line in lst: 
    for li in line: 
     another_lst.append(li.strip()) 

print() 
print() 
print(another_lst) 

word = random.choice(lst) 
theWord = word 

jumble = "" 
while(len(word)>0): 
    position = random.randrange(len(word)) 
    jumble+=word[position] 
    word=word[:position]+word[position+1:] 
print("The jumble word is: {}".format(jumble)) 

#Getting player's guess 
guess = input("Enter your guess: ") 

#congratulate the player 
if(guess==theWord): 
    print("Congratulations! You guessed it") 
else: 
    print ("Sorry, wrong guess.") 

input("Thanks for playing. Press the enter key to exit.")