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我的問題是,我似乎無法獲得我需要的節點列表。我嘗試了多種解決方案,但似乎並不奏效。這是我的xml文件的一部分:在XML中找不到某個節點
<findItemsByCategoryResponse xmlns="http://www.ebay.com/marketplace/search/v1/services">
<ack>Success</ack>
<version>1.13.0</version>
<timestamp>2016-08-23T07:33:22.497Z</timestamp>
<searchResult count="100">
<item>
<itemId>152210133431</itemId>
<title>...</title>
<globalId>EBAY-GB</globalId>
<primaryCategory>
<categoryId>218</categoryId>
<categoryName>Magic the Gathering</categoryName>
</primaryCategory>
<galleryURL>
http://thumbs4.ebaystatic.com/m/meIDrVqhmbpQMYCxzeUvR9Q/140.jpg
</galleryURL>
<viewItemURL>
http://www.ebay.co.uk/itm/MTG-See-Unwritten-Khans-Tarkir-MYTHIC-MINT-/152210133431
</viewItemURL>
<paymentMethod>PayPal</paymentMethod>
<autoPay>false</autoPay>
<location>London,United Kingdom</location>
<country>GB</country>
<shippingInfo>
<shippingServiceCost currencyId="GBP">1.1</shippingServiceCost>
<shippingType>Flat</shippingType>
<shipToLocations>GB</shipToLocations>
</shippingInfo>
<sellingStatus>
<currentPrice currencyId="GBP">0.5</currentPrice>
<convertedCurrentPrice currencyId="GBP">0.5</convertedCurrentPrice>
<bidCount>0</bidCount>
<sellingState>Active</sellingState>
<timeLeft>P0DT0H19M12S</timeLeft>
</sellingStatus>
<listingInfo>
<bestOfferEnabled>false</bestOfferEnabled>
<buyItNowAvailable>false</buyItNowAvailable>
<startTime>2016-08-18T07:52:34.000Z</startTime>
<endTime>2016-08-23T07:52:34.000Z</endTime>
<listingType>Auction</listingType>
<gift>false</gift>
</listingInfo>
<condition>
<conditionId>1000</conditionId>
<conditionDisplayName>New</conditionDisplayName>
</condition>
<isMultiVariationListing>false</isMultiVariationListing>
<topRatedListing>false</topRatedListing>
</item>
</searchResult>
<paginationOutput>...</paginationOutput>
<itemSearchURL>...</itemSearchURL>
</findItemsByCategoryResponse>
通常有這xml文件100個節點,我只是短的文件。我試圖在XmlNodeList中獲取''item''節點和一切內容,但是當我調試它時說它包含0個項目。在此之後,我想要檢索一些數據,如代碼中所示。注意:我嘗試了很多xpath值! 這裏是我使用的代碼:
XmlDocument xmlText = new XmlDocument();
xmlText.Load(basicUrl);
XmlElement root = xmlText.DocumentElement;
XmlNodeList xnList = root.SelectNodes("//item");
foreach(XmlNode item in xnList)
{
string title = item["title"].InnerText;
Console.WriteLine(title);
}
如何解釋_why_這將/能夠幫助? –
不太明白,它似乎不起作用,你能給我多一點信息?或者可能用linq而不是Xpath來搜索它? – Wouter
Xpath是一種在XML中進行搜索的非常好的方法我編輯了我的答案(我使用問題中提供的xml測試了代碼) –