我完全停留在我期望的簡單問題上。當$ filepath變量是要上載的文件的絕對路徑並在腳本中定義時,以下Amazon AWS SDK2腳本將文件成功上傳到AWS S3。PHP:將變量傳遞給AWS SDK2上傳器
但是,當我嘗試使用簡單的表單來選擇文件並將其作爲變量傳遞給AWS腳本時,我將自己束縛在節點上。例如試圖使用$ _FILES ['input1'] ['name'],$ _FILES ['input1'] ['tmp_name'],realpath(),file_get_contents()來訪問完整路徑。還嘗試使用JavaScript,但路徑然後由瀏覽器更改爲'假路徑'。我顯然不明白元素中的type =「file」。
所以,我的問題:如何讓用戶從本地磁盤選擇文件並(使用POST操作??)將文件路徑作爲變量傳遞給AWS SDK2上傳腳本?我的簡單測試表格也包含在下面。
簡單形式:
<body>
<form id="form1" action="SDK2_script_process.php" method="post" enctype="multipart/form-data">
<input type="file" id="input1" name="input1" />
<input type="submit" name="submit" id="submit" value="Search" >
</form> </body>
過程腳本(SDK2_script_process.php):
<?php
//CONNECTS TO AWS V2 SDK AND UPLOADS FILE
//Literal path to aws.phar file
require_once 'AWSSDKforPHP/aws.phar';
use Aws\S3\S3Client;
use Guzzle\Http\EntityBody;
// Instantiate the S3 client with AWS credentials and optional desired AWS region
$client = S3Client::factory(array(
'key' => 'MYKEY',
'secret' => MYSECRETKEY'
));
//Name of bucket on S3
$bucket = 'mybucket';
//Filename to be saved in S3 Bucket
$filename = "/directoryA/directoryB/filename.extension";
//Literal filepath to file I want to save - THIS WORKS
// $filepath = '../../directory1/directory2/directory3/filename.extension';
// Filepath from simple form - DOES NOT WORK
$filepath = $_FILES['input1']['tmp_name'];
$result = $client->putObject(array(
'Bucket' => $bucket,
'Key' => $filename,
'SourceFile' => $filepath,
'Metadata' => array(
'title' => 'This is the title metadata',
'artist' => 'This is the artist metadata'
)
));
// HEAD object confirms success
$headers = $client->headObject(array(
"Bucket" => $bucket,
"Key" => $filename
));
//print_r($headers->toArray());
echo $result['ObjectURL'];
echo $headers['Metadata']['artist'];
?>
欣賞任何幫助,或指針使用這種SDK2腳本的不同方式。