MySQL查詢選擇分鐘日期時間30天的間隔

Question

下面是一些轉儲數據分組..

CREATE TABLE `customer` (
    `approve_datetime` datetime DEFAULT NULL, 
    `created_date` date DEFAULT NULL 
) ENGINE=InnoDB DEFAULT CHARSET=latin1; 

INSERT INTO `customer` (`approve_datetime`, `created_date`) 
VALUES 
    ('2015-08-20 04:43:00','2015-08-20'), 
    (NULL,'2015-09-03'), 
    ('2015-09-17 02:17:00','2015-09-17'), 
    (NULL,'2015-09-29'), 
    ('2015-09-29 12:44:00','2015-09-29'), 
    ('2015-10-08 03:09:00','2015-10-08'), 
    ('2016-01-20 08:59:00','2016-01-19'), 
    ('2016-05-03 09:38:00','2016-05-02'), 
    ('2016-07-15 11:06:00','2016-07-15'), 
    (NULL,'2016-08-30'), 
    ('2016-10-18 12:55:00','2016-10-18'), 
    (NULL,'2017-01-08'), 
    (NULL,'2017-02-02'), 
    ('2017-02-13 02:58:00','2017-02-13'); 

這是不正確處理在30天的分組我當前的查詢。

SELECT a.* 
FROM customer a 
WHERE a.approve_datetime IN (
     SELECT MIN(b.approve_datetime) 
     FROM customer b 
     WHERE b.created_date BETWEEN a.created_date 
      AND DATE_ADD(a.created_date, INTERVAL 30 DAY) 
    ) 

這給了我以下。

+---------------------+--------------+ 
| approve_datetime | created_date | 
+---------------------+--------------+ 
| 2015-08-20 04:43:00 | 2015-08-20 | 
| 2015-09-17 02:17:00 | 2015-09-17 | 
| 2015-09-29 12:44:00 | 2015-09-29 | 
| 2015-10-08 03:09:00 | 2015-10-08 | 
| 2016-01-20 08:59:00 | 2016-01-19 | 
| 2016-05-03 09:38:00 | 2016-05-02 | 
| 2016-07-15 11:06:00 | 2016-07-15 | 
| 2016-10-18 12:55:00 | 2016-10-18 | 
| 2017-02-13 02:58:00 | 2017-02-13 | 
+---------------------+--------------+ 

是否可以更改查詢以實現以下結果？

+---------------------+--------------+ 
| approve_datetime | created_date | 
+---------------------+--------------+ 
| 2015-08-20 04:43:00 | 2015-08-20 | 
| 2015-09-29 12:44:00 | 2015-09-29 | 
| 2016-01-20 08:59:00 | 2016-01-19 | 
| 2016-05-03 09:38:00 | 2016-05-02 | 
| 2016-07-15 11:06:00 | 2016-07-15 | 
| 2016-10-18 12:55:00 | 2016-10-18 | 
| 2017-02-13 02:58:00 | 2017-02-13 | 
+---------------------+--------------+ 

注意與CREATED_DATE的2015年9月17日和2015年10月8日已被刪除，因爲它們中的前記錄下哪些是特定羣體的最低日起30日內記錄。 2015-08-20 + 30天從第一組開始，2015-08-20是該組的最短日期。

我希望我想要實現的是有道理的。

Answer 1

看看這個。結果是不同的，但看看這是否正確。第3欄和第4欄只是看它是如何工作的。

SELECT 
     min(b.approve_datetime) AS approve_datetime 
    , min(b.created_date) AS created_date 
    , DATEDIFF(b.created_date,(SELECT min(created_date) FROM customer))/30 AS dayd30 
    , FLOOR(DATEDIFF(b.created_date,(SELECT min(created_date) FROM customer))/30) AS dayd30floorint 
    FROM customer b 
    GROUP BY FLOOR(DATEDIFF(b.created_date,(SELECT min(created_date) FROM customer))/30) 
    ORDER BY b.created_date ; 

樣品

MariaDB [testdb]> SELECT 
    ->  min(b.approve_datetime) AS approve_datetime 
    ->  , min(b.created_date) AS created_date 
    ->  , DATEDIFF(b.created_date,(SELECT min(created_date) FROM customer))/30 AS dayd30 
    ->  , FLOOR(DATEDIFF(b.created_date,(SELECT min(created_date) FROM customer))/30) AS dayd30floorint 
    ->  FROM customer b 
    ->  GROUP BY FLOOR(DATEDIFF(b.created_date,(SELECT min(created_date) FROM customer))/30) 
    ->  ORDER BY b.created_date ; 
+---------------------+--------------+---------+----------------+ 
| approve_datetime | created_date | dayd30 | dayd30floorint | 
+---------------------+--------------+---------+----------------+ 
| 2015-08-20 04:43:00 | 2015-08-20 | 0.0000 |    0 | 
| 2015-09-29 12:44:00 | 2015-09-29 | 1.3333 |    1 | 
| 2016-01-20 08:59:00 | 2016-01-19 | 5.0667 |    5 | 
| 2016-05-03 09:38:00 | 2016-05-02 | 8.5333 |    8 | 
| 2016-07-15 11:06:00 | 2016-07-15 | 11.0000 |    11 | 
| NULL    | 2016-08-30 | 12.5333 |    12 | 
| 2016-10-18 12:55:00 | 2016-10-18 | 14.1667 |    14 | 
| NULL    | 2017-01-08 | 16.9000 |    16 | 
| NULL    | 2017-02-02 | 17.7333 |    17 | 
| 2017-02-13 02:58:00 | 2017-02-13 | 18.1000 |    18 | 
+---------------------+--------------+---------+----------------+ 
10 rows in set (0.00 sec) 

MariaDB [testdb]>