我想箱子一個應用程序從Twitter進行身份驗證,但我得到以下錯誤 :的Twitter的Oauth失敗,原因是簽名和令牌
Failed to validate oauth signature and token
這裏是我的應用程序代碼:
public class TwitCons {
String sign_method ="HMAC-SHA1";
public static String consumer_key ="^^^^^^^^^^^^^^^^^^^^";
public static String consumer_secret="^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^";
String request_uri = "https://api.twitter.com/oauth/request_token";
String oauth_callback="http://127.0.0.1:8080/twitter/getToken";
String getNonce(){
Random ran = new Random();
long nonce1 = ran.nextLong();
Long nonce = Math.abs(new Long(nonce1));
return nonce.toString();
}
String getTimestamp(){
long time = System.currentTimeMillis();
return String.valueOf(time/1000);
}
String getSignature(String request_uri ,String request_token,String nonce) throws UnsupportedEncodingException
{
String base="oauth_callback=http://127.0.0.1:8080/twitter/getToken&oauth_consumer_key="+consumer_key+"&oauth_nonce="+nonce+"&oauth_signature_method="+sign_method+"&oauth_timestamp="+getTimestamp()+"&oauth_token=&oauth_version=1.0";
String baseString="POST&"+URLEncoder.encode(request_uri , "UTF-8")+"&"+URLEncoder.encode(base , "UTF-8");
String signKey = consumer_secret +"&"+ request_token ;
System.out.println(signKey +"\n"+baseString);
try {
SecretKeySpec signingKey = new SecretKeySpec(signKey.getBytes(),"HmacSHA1");
Mac mac = Mac.getInstance(signingKey.getAlgorithm());
mac.init(signingKey);
byte[] rawHmac = mac.doFinal(baseString.getBytes());
String result = new String(Base64.encodeBase64(rawHmac));
System.out.println(URLEncoder.encode(result , "UTF-8"));
return URLEncoder.encode(result , "UTF-8");
//return result;
} catch (GeneralSecurityException e) {
return "";
}
}
}
和
public class Twitter extends TwitCons{
public void getRequest() throws IllegalArgumentException, HttpException, IOException
{
HttpClient client = new HttpClient();
PostMethod post = new PostMethod("https://api.twitter.com/oauth/request_token");
String nonce=getNonce();
String header = "oauth_callback=\""+URLEncoder.encode(oauth_callback ,"UTF-8")+"\","+
"oauth_consumer_key=\""+consumer_key +"\","+
"oauth_nonce=\""+nonce + "\","+
"oauth_signature=\""+getSignature(request_uri,"",nonce) + "\","+
"oauth_signature_method=\""+sign_method + "\","+
"oauth_timestamp=\""+getTimestamp() + "\","+
"oauth_version=\"1.0\"" ;
post.addRequestHeader("Authorization", "OAuth "+header);
client.executeMethod(post);
System.out.println(post.getResponseBodyAsString()+"\n"+post.getRequestHeader("Authorization"));
}
類有方法getRequest用於使twitte在r要求越來越request_token和token_secret
和第二類TwitCons有不同的方法和常量來獲得請求令牌
錯誤。所有經過驗證的請求都需要'oauth_token',而'POST https:// api.twitter.com/oauth/request_token'則需要'oauth_token'。這是合乎邏輯的,因爲您要求提供OAuth令牌。 ;-) – 2012-07-08 18:08:45
該死的,我把它與OAuth2流,您首先重定向用戶,然後請求訪問令牌;)我將更新與另一個建議的帖子... – 2012-07-08 18:30:40
我已經嘗試了所有這些事情,但仍然得到同樣的錯誤又一次... – behinddwalls 2012-07-09 10:58:10